(This thread refers to "Bivariate Normal Distribution - Oct.10 )
[as an example for a bivariate N~distr.: Y ~N (µ=15.73, s= 7.24) , X ~N (µ=14.17, s= 8.19), r(X,Y) = -0.047] I have a table of 5 columns. The five columns contain statistical moments of two intercorrelated Normal distributions: µ(1), µ(2), s(1),s(2), r(1,2). Where µ(1) is the mean of distribution 1 (X), µ(2) is the mean of distribution 2 (Y), s(1) is the standard deviation of distribution 1 (X), s(2) is the standard deviation of distribution 2 (Y), r(1,2) is the correlation (Pearson) between distribution 1 and distribution 2 (X,Y). Does anyone have a suggestion (or a syntax example) how to compute what proportion of the bivariate distribution is in the range (Y>X+1) Data example: case µ1 µ2 s1 s2 r proportion 1 15.73 14.17 7.24 8.17 -0.047 ? 2 16.12 15.56 8.14 9.32 -0.056 ? 3 17.78 11.47 6.34 7.78 -0.037 ? 4 14.98 19.32 6.24 6.56 -0.097 ? 5 12.32 21.84 4.24 6.56 -0.044 ? Thank you.
Dr. Frank Gaeth
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Administrator
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First of all in the future,
Please continue the earlier thread to maintain context rather than beginning a new thread. No fish today, just 2 helpful prods with the clue stick. --- Hint: The difference of 2 normally distributed variables is also normally distributed. The variance of a linear combination is C1**2*Var1+C2**2*Var2+ 2*C1*C2*Cov(Var1,Var2) Where C1=1 and C2=-1 in this case. ---
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