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Hi All,
I am wondering if someone can answer/explain the following to me. I am running a 2 x 2 Pearson Chi square test with the following variables: - Genotype?= + or yes (coded value =1) /- or no (coded value = 0) - History of IV drug use/abuse?= + or yes(coded value =1) /- or no (coded value = 0) I have used SPSS "Crosstabs" from the Descriptives menu in the past to derive Pearson chi square values and accompanying significance levels, but in version 15.0 there is an independent chi square?procedure under the "Nonparametric Tests" Menu. I have run analyses using each method and my results?are conflicting.?Specifically, under the "Crosstabs" option,?my result is Pearson Chi-square (1) = 4.27, p = .023, wheras under the "Nonparametric" option?my result is?Pearson Chi-square (1) = 2.86, p = .091. If it is of relevance my sample is as follows: ???????????????????????IV DRUG USE/ABUSE ??????????????????????????????????? NO / YES ????? GENOTYPE?--?NO???=? 19 /? = 7 ???????????????????????? YES?=?? 15 /? = 0 Total N = 41. Can anyone explain why the discrepant Pearson Chi Square?results and which is more valid and appropriate to report? Thanks very much in advance for your feedback. Ken ===================== To manage your subscription to SPSSX-L, send a message to [hidden email] (not to SPSSX-L), with no body text except the command. To leave the list, send the command SIGNOFF SPSSX-L For a list of commands to manage subscriptions, send the command INFO REFCARD |
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Hi list,
I know that this question is not 100% related to SPSS, but maybe somebody could provide any help on it!!! I have a prevalence (or cross-sectional study) where two dependent variables (i.e. hepatitis B and hepatitis C) and three independent variables have been measured (ie. sex, race, and drug use). In my analysis, I have performed two logistic regression models: hepatitis C = bo+b1(sex)+b2(race)+b3(drug use) hepatitis B = bo+b4(sex)+b5(race)+b6(drug use) in this study, the measurement (or independent variables) have been taken simultaneously, but we are measuring two different outcomes. So, I'd like to estimate a parameter for the difference in the effect of a covariate (eg. sex) on hepatitis C and hepatiti B virus. Why Do I need this? because, these differences could be informative. any thoughs? thanks in advance, /Christian ===================== To manage your subscription to SPSSX-L, send a message to [hidden email] (not to SPSSX-L), with no body text except the command. To leave the list, send the command SIGNOFF SPSSX-L For a list of commands to manage subscriptions, send the command INFO REFCARD |
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In reply to this post by Ken Belzer
If I understand your table, the cells are
19 7 15 0 Is that correct? You want to use the Crosstabs result, not the Npar Test result. Also, because of the relatively small sample size, you might look at the p-value associated with Fisher's exact test. Anthony Babinec [hidden email] "Fermentation and civilization are inseparable." John Ciardi -----Original Message----- From: SPSSX(r) Discussion [mailto:[hidden email]] On Behalf Of Ken Belzer Sent: Friday, March 28, 2008 10:48 AM To: [hidden email] Subject: Chi Square -- Crosstabs versus Nonparametric Hi All, I am wondering if someone can answer/explain the following to me. I am running a 2 x 2 Pearson Chi square test with the following variables: - Genotype?= + or yes (coded value =1) /- or no (coded value = 0) - History of IV drug use/abuse?= + or yes(coded value =1) /- or no (coded value = 0) I have used SPSS "Crosstabs" from the Descriptives menu in the past to derive Pearson chi square values and accompanying significance levels, but in version 15.0 there is an independent chi square?procedure under the "Nonparametric Tests" Menu. I have run analyses using each method and my results?are conflicting.?Specifically, under the "Crosstabs" option,?my result is Pearson Chi-square (1) = 4.27, p = .023, wheras under the "Nonparametric" option?my result is?Pearson Chi-square (1) = 2.86, p = .091. If it is of relevance my sample is as follows: ???????????????????????IV DRUG USE/ABUSE ??????????????????????????????????? NO / YES ????? GENOTYPE?--?NO???=? 19 /? = 7 ???????????????????????? YES?=?? 15 /? = 0 Total N = 41. Can anyone explain why the discrepant Pearson Chi Square?results and which is more valid and appropriate to report? Thanks very much in advance for your feedback. Ken ===================== To manage your subscription to SPSSX-L, send a message to [hidden email] (not to SPSSX-L), with no body text except the command. To leave the list, send the command SIGNOFF SPSSX-L For a list of commands to manage subscriptions, send the command INFO REFCARD ===================== To manage your subscription to SPSSX-L, send a message to [hidden email] (not to SPSSX-L), with no body text except the command. To leave the list, send the command SIGNOFF SPSSX-L For a list of commands to manage subscriptions, send the command INFO REFCARD |
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In reply to this post by cbautista
Hi Christian:
All data should be together in one dataset. You need a variable (called hepatitis) with values 0=B and 1=C (or just the opposite, it doesn't mind). Run a logistic model with all the predictors (sex, race and drug use) plus the new variable hepatitis. To see if sex effect (for instance) is equal in both hepatitis groups, add an interaction term between hepatitis and sex. If it is significant, then the two betas are statistically different. HTH, Marta > Hi list, > > I know that this question is not 100% related to SPSS, but maybe somebody > could provide any help on it!!! > > I have a prevalence (or cross-sectional study) where two dependent > variables (i.e. hepatitis B and hepatitis C) and three independent > variables have been measured (ie. sex, race, and drug use). In my > analysis, I have performed two logistic regression models: > > hepatitis C = bo+b1(sex)+b2(race)+b3(drug use) > hepatitis B = bo+b4(sex)+b5(race)+b6(drug use) > > in this study, the measurement (or independent variables) have been taken > simultaneously, but we are measuring two different outcomes. > > So, I'd like to estimate a parameter for the difference in the effect of a > covariate (eg. sex) on hepatitis C and hepatiti B virus. Why Do I need > this? because, these differences could be informative. > > any thoughs? > > thanks in advance, > > /Christian > > ===================== > To manage your subscription to SPSSX-L, send a message to > [hidden email] (not to SPSSX-L), with no body text except the > command. To leave the list, send the command > SIGNOFF SPSSX-L > For a list of commands to manage subscriptions, send the command > INFO REFCARD > > ===================== To manage your subscription to SPSSX-L, send a message to [hidden email] (not to SPSSX-L), with no body text except the command. To leave the list, send the command SIGNOFF SPSSX-L For a list of commands to manage subscriptions, send the command INFO REFCARD |
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In reply to this post by cbautista
Hi again
Reading my message (unfortunately, after I had hit "Send"), I realized my explanation might be a bit misguiding, because I assumed that there were two independent cross-sectional studies, but you have ONE study with two outcomes, and there might even be cases with both diseases at the same time. Now I see it is a rather complicated problem, because you have somehow "paired" betas to test, not independent, as my previous message assumed. Give me some time, and I will try to ask an epidemiologist (who studied with Hosmer & Lemeshow time ago) at the University about your problem. Although he is usually very busy, he owes me some SPSS favors ;) Best regards. Marta > Hi list, > > I know that this question is not 100% related to SPSS, but maybe somebody > could provide any help on it!!! > > I have a prevalence (or cross-sectional study) where two dependent > variables (i.e. hepatitis B and hepatitis C) and three independent > variables have been measured (ie. sex, race, and drug use). In my > analysis, I have performed two logistic regression models: > > hepatitis C = bo+b1(sex)+b2(race)+b3(drug use) > hepatitis B = bo+b4(sex)+b5(race)+b6(drug use) > > in this study, the measurement (or independent variables) have been taken > simultaneously, but we are measuring two different outcomes. > > So, I'd like to estimate a parameter for the difference in the effect of a > covariate (eg. sex) on hepatitis C and hepatiti B virus. Why Do I need > this? because, these differences could be informative. > > any thoughs? > > thanks in advance, > > /Christian > > ===================== > To manage your subscription to SPSSX-L, send a message to > [hidden email] (not to SPSSX-L), with no body text except the > command. To leave the list, send the command > SIGNOFF SPSSX-L > For a list of commands to manage subscriptions, send the command > INFO REFCARD > > ===================== To manage your subscription to SPSSX-L, send a message to [hidden email] (not to SPSSX-L), with no body text except the command. To leave the list, send the command SIGNOFF SPSSX-L For a list of commands to manage subscriptions, send the command INFO REFCARD |
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In reply to this post by cbautista
Hi Christian:
My friend's reply. z = [ln(OR1) -ln(OR2)] / [(SE12+SE22)0.5] (Schlesselman JJ. Case-control studies. Design, conduct, analysis. Oxford: Oxford University Press, 1982). HTH, Marta > Hi list, > > I know that this question is not 100% related to SPSS, but maybe somebody > could provide any help on it!!! > > I have a prevalence (or cross-sectional study) where two dependent > variables (i.e. hepatitis B and hepatitis C) and three independent > variables have been measured (ie. sex, race, and drug use). In my > analysis, I have performed two logistic regression models: > > hepatitis C = bo+b1(sex)+b2(race)+b3(drug use) > hepatitis B = bo+b4(sex)+b5(race)+b6(drug use) > > in this study, the measurement (or independent variables) have been taken > simultaneously, but we are measuring two different outcomes. > > So, I'd like to estimate a parameter for the difference in the effect of a > covariate (eg. sex) on hepatitis C and hepatiti B virus. Why Do I need > this? because, these differences could be informative. > > any thoughs? > > thanks in advance, > > /Christian > > ===================== > To manage your subscription to SPSSX-L, send a message to > [hidden email] (not to SPSSX-L), with no body text except the > command. To leave the list, send the command > SIGNOFF SPSSX-L > For a list of commands to manage subscriptions, send the command > INFO REFCARD > > ===================== To manage your subscription to SPSSX-L, send a message to [hidden email] (not to SPSSX-L), with no body text except the command. To leave the list, send the command SIGNOFF SPSSX-L For a list of commands to manage subscriptions, send the command INFO REFCARD |
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