Hi Dan,
Tentatively, because playing with infinities and 0 is potentially risky, so using a calculator:
If first variable = 0, then exp0 = 1 and then 1/exp0 = 1.
If first variable = 20, say, then exp20 = 485165195.4 and 1/exp20 = 0.000000009.
So, as first variable 'x' increases towards +Inf, the function 1/exp(x) tends towards 0 and does not go below 0.
So, if x= 0, 1/exp(0) =1 and if x=+Inf, 1/exp(+Inf) = 0 as required. This assumes that x lies between 0 and +Inf: you'd need to check with any potential -ve x's as to whether the function does what
you want it to do.
Martin Holt
Medical Statistician
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