--The SPSS module of the Python module has a
SetMacroValue function. That's probably the nicest way
to do it, but I can't tell you (yet) how exactly it
should be done.
--This is another way:
get file='C:\Program Files\Spss\Employee data.sav'.
n of cases 1.
flip.
compute dummy = 1.
aggregate outfile = * / break = dummy / n = n.
print outfile = "d:\temp\number.sps" / "define
n_of_vars () " n "!enddefine.".
exe.
insert file = "d:\temp\number.sps" .
exe.
display macros.
Cheers!!
Albert-Jan
--- Sasha <
[hidden email]> wrote:
> In the syntax below, "88" should be replaced with
> another number as a
> result of preceeding calculations.
>
>
> CORRESPONDENCE Table = all( 7, 88)
> /DIMENSIONS = 2
> /MEASURE = CHISQ
> /STANDARDIZE = RCMEAN
> /NORMALIZATION = SYMMETRICAL
> /PRINT = TABLE RPOINTS CPOINTS
> /PLOT = NDIM(1,2) BIPLOT(20) .
>
>
> For instance I precaluclated num_of_vars = number of
> variables:
>
> compute num_of_vars=0.
> exe.
> do repeat var=all.
> compute num_of_vars=num_of_vars+1.
> end repeat.
> exe.
>
> Now, num_of_vars contains the actual number of
> variables in the dataset.
> How can I replace "88" in the syntax above with this
> value in the
> num_of_vars variable?
>
> I tried to do that through defining macro with
> arguments, but it doesn't
> seem to work with values of variables.
>
> Can anyone help, please?
>
Cheers!
Albert-Jan
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Did you know that 87.166253% of all statistics claim a precision of results that is not justified by the method employed? [HELMUT RICHTER]
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