Increment

[Roger Cupido]

Hello Everyone

I have a multiple question with 28 answer options. I want to identify respondents with 3 or more than 3 "yes" answers for any of the 28 options and create a new variable. The syntax identifies the "yes" (1) but fails to increment and identify more than 3 "yes" answers for one respondent.

I wrote the following syntax:

COMPUTE YesCount = 0.
VECTOR  v1=S3Q3A.1 to S3Q3A.28.
LOOP #N = 0 to 28.
IF ((#n)=1) YesCount = + 1.
END LOOP.
EXECUTE.

Please help and thanks in advance...

[Jon K Peck]

You are testing the loop counter, #n, not the variable.

Jon Peck (no "h") aka Kim
Senior Software Engineer, IBM
[hidden email]
new phone: [phone]




From:        SPSS_Tech <[hidden email]>
To:        [hidden email]
Date:        02/20/2012 07:24 AM
Subject:        [SPSSX-L] Increment
Sent by:        "SPSSX(r) Discussion" <[hidden email]>

---

Hello Everyone

I have a multiple question with 28 answer options. I want to identify
respondents with 3 or more than 3 "yes" answers for any of the 28 options
and create a new variable. The syntax identifies the "yes" (1) but fails to
increment and identify more than 3 "yes" answers for one respondent.

I wrote the following syntax:

COMPUTE YesCount = 0.
VECTOR  v1=S3Q3A.1 to S3Q3A.28.
LOOP #N = 0 to 28.
IF ((#n)=1) YesCount = + 1.
END LOOP.
EXECUTE.

Please help and thanks in advance...



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[Art Kendall]

something like this untested syntax should be more readable.
count YesCount = S3Q3A.1 to S3Q3A.28(1).
compute ge_3_yeses + Yescount ge 3.

Art Kendall
Social Research Consultants


On 2/20/2012 9:16 AM, SPSS_Tech wrote:

> Hello Everyone
>
> I have a multiple question with 28 answer options. I want to identify
> respondents with 3 or more than 3 "yes" answers for any of the 28 options
> and create a new variable. The syntax identifies the "yes" (1) but fails to
> increment and identify more than 3 "yes" answers for one respondent.
>
> I wrote the following syntax:
>
> COMPUTE YesCount = 0.
> VECTOR  v1=S3Q3A.1 to S3Q3A.28.
> LOOP #N = 0 to 28.
> IF ((#n)=1) YesCount = + 1.
> END LOOP.
> EXECUTE.
>
> Please help and thanks in advance...
>
>
>
> --
> View this message in context: http://spssx-discussion.1045642.n5.nabble.com/Increment-tp5499172p5499172.html
> Sent from the SPSSX Discussion mailing list archive at Nabble.com.
>
> =====================
> To manage your subscription to SPSSX-L, send a message to
> [hidden email] (not to SPSSX-L), with no body text except the
> command. To leave the list, send the command
> SIGNOFF SPSSX-L
> For a list of commands to manage subscriptions, send the command
> INFO REFCARD
>

=====================
To manage your subscription to SPSSX-L, send a message to
[hidden email] (not to SPSSX-L), with no body text except the
command. To leave the list, send the command
SIGNOFF SPSSX-L
For a list of commands to manage subscriptions, send the command
INFO REFCARD

[David Marso]

Keep it simple!
COUNT YesCount=S3Q3A.1 to S3Q3A.28 (1).

OTOH: To answer your question:
COMPUTE YesCount = 0.
VECTOR  v1=S3Q3A.1 to S3Q3A.28.
LOOP #N = 0 to 28.
+  IF v1(#n) EQ 1) YesCount = YesCount+ 1.
END LOOP.
EXECUTE.

I tend to write it as (I avoid affixing numbers to vectors and unnecessary logic):
VECTOR  v=S3Q3A.1 to S3Q3A.28.
LOOP #N = 0 to 28.
+  COMPUTE YesCount=SUM(YesCount, v(#n) EQ 1).
END LOOP.

SPSS_Tech wrote

Hello Everyone

I have a multiple question with 28 answer options. I want to identify respondents with 3 or more than 3 "yes" answers for any of the 28 options and create a new variable. The syntax identifies the "yes" (1) but fails to increment and identify more than 3 "yes" answers for one respondent.

I wrote the following syntax:

COMPUTE YesCount = 0.
VECTOR  v1=S3Q3A.1 to S3Q3A.28.
LOOP #N = 0 to 28.
IF ((#n)=1) YesCount = + 1.
END LOOP.
EXECUTE.

Please help and thanks in advance...

[Rich Ulrich]

As has been posted, use Count.

Just for completeness -

Your SPSS code has 3 mistakes in two lines. 

The Loop index, as a subscript in SPSS, must be from 1, not from 0.
Your variables run from  ...1  to ...28, so your code (0 to 28)
was not correct in any language.

As has been mentioned, your IF test is done on #N and not
on v1(#N). 

To increment YesCount, you want to set YesCount
to YesCount+1,  not to "+1".

--
Rich Ulrich

> Date: Mon, 20 Feb 2012 06:16:50 -0800

> From: [hidden email]
> Subject: Increment
> To: [hidden email]
>
> Hello Everyone
>
> I have a multiple question with 28 answer options. I want to identify
> respondents with 3 or more than 3 "yes" answers for any of the 28 options
> and create a new variable. The syntax identifies the "yes" (1) but fails to
> increment and identify more than 3 "yes" answers for one respondent.
>
> I wrote the following syntax:
>
> COMPUTE YesCount = 0.
> VECTOR v1=S3Q3A.1 to S3Q3A.28.
> LOOP #N = 0 to 28.
> IF ((#n)=1) YesCount = + 1.
> END LOOP.
> EXECUTE.
>
> Please help and thanks in advance...
>
> ...

[David Marso]

Great catch on the 0 Rich ;-)
I was blind sighted by the other stuff and didn't even notice it ;-(

Rich Ulrich-2 wrote

As has been posted, use Count.

Just for completeness -


Your SPSS code has 3 mistakes in two lines.  

The Loop index, as a subscript in SPSS, must be from 1, not from 0.
Your variables run from  ...1  to ...28, so your code (0 to 28)
was not correct in any language.

As has been mentioned, your IF test is done on #N and not
on v1(#N).  

To increment YesCount, you want to set YesCount
to YesCount+1,  not to "+1".

--
Rich Ulrich

> Date: Mon, 20 Feb 2012 06:16:50 -0800
> From: [hidden email]
> Subject: Increment
> To: [hidden email]
>
> Hello Everyone
>
> I have a multiple question with 28 answer options. I want to identify
> respondents with 3 or more than 3 "yes" answers for any of the 28 options
> and create a new variable. The syntax identifies the "yes" (1) but fails to
> increment and identify more than 3 "yes" answers for one respondent.
>
> I wrote the following syntax:
>
> COMPUTE YesCount = 0.
> VECTOR  v1=S3Q3A.1 to S3Q3A.28.
> LOOP #N = 0 to 28.
> IF ((#n)=1) YesCount = + 1.
> END LOOP.
> EXECUTE.
>
> Please help and thanks in advance...
>
> ...

[Roger Cupido]

Thanks to everyone for helping.

Much appreciated.

Regards,
Roger