Good Evening Everyone,
I hope someone will guide me around this simple problem that fell in front of me today. Which t test do I want to report? I have two groups: Group1 n= 1,512 M=2.5668 SD1=.80339 Group2 n= 273 M=2.3187 SD2=.96877 Levene's Test for Equality of Variance F= 27.531, p<.0001. 1) Equal Variances Assumed t(1783) = 4.542, p <.001. 2) Equal Variances NOT Assumed t(342.79) = 3.991. The large N has created a statistically significance difference out of a trivial difference; furthermore, the variances between the groups are statistically different. Can Levene's result be ignored because of the large sample or is it recommended that I report t test #2? I would appreciate any suggestions and, if possible, references on this problem. I thank you in advance. Stephen Salbod, Pace University |
The main point, I think, is that your conclusion stands either under
the equal variances or the unequal variances hypotheses. This is, of course, in part due to the fact that your sample is large. And that is a good thing. Now, to report your results you may choose one hypothesis or another about the equality of variances (both leading to the same substantive conclusion). Since (at your sample size) the variances observed in the groups lend credence to the different-variances hypothesis, i.e. the difference in variances is statistically significant, you may want to use that one for reporting purposes. Finding different variances is not altogether surprising. I imagine your results do not come from any randomized experimental design, but from some observational study, so it would be mere fluke that your groups show equal variances. One should rather EXPECT different variances (as one would rather expect different group sizes) for the various groups. Hector -----Mensaje original----- De: SPSSX(r) Discussion [mailto:[hidden email]] En nombre de Stephen Salbod Enviado el: 23 March 2007 23:04 Para: [hidden email] Asunto: Levene test with large sample Good Evening Everyone, I hope someone will guide me around this simple problem that fell in front of me today. Which t test do I want to report? I have two groups: Group1 n= 1,512 M=2.5668 SD1=.80339 Group2 n= 273 M=2.3187 SD2=.96877 Levene's Test for Equality of Variance F= 27.531, p<.0001. 1) Equal Variances Assumed t(1783) = 4.542, p <.001. 2) Equal Variances NOT Assumed t(342.79) = 3.991. The large N has created a statistically significance difference out of a trivial difference; furthermore, the variances between the groups are statistically different. Can Levene's result be ignored because of the large sample or is it recommended that I report t test #2? I would appreciate any suggestions and, if possible, references on this problem. I thank you in advance. Stephen Salbod, Pace University |
In reply to this post by Salbod
I think you should report the F-test. Having said that, if you are
concerned with the test results; you should also rely on the traditional plots of your residuals against the predictors and the fitted response variable. If the plots show the typical pattern of non constant variances then the data validates the results of the test. But if these plots contradict the test results you may want to also add a comment to your results. I am coming to the conclusion that the plots tell the story better. Another possibility for test results to contradict your plots could be an improper model specification or omission of an important predictor. Fermin Ornelas, Ph.D. Management Analyst III, AZ DES Tel: (602) 542-5639 E-mail: [hidden email] -----Original Message----- From: SPSSX(r) Discussion [mailto:[hidden email]] On Behalf Of Stephen Salbod Sent: Friday, March 23, 2007 3:04 PM To: [hidden email] Subject: Levene test with large sample Good Evening Everyone, I hope someone will guide me around this simple problem that fell in front of me today. Which t test do I want to report? I have two groups: Group1 n= 1,512 M=2.5668 SD1=.80339 Group2 n= 273 M=2.3187 SD2=.96877 Levene's Test for Equality of Variance F= 27.531, p<.0001. 1) Equal Variances Assumed t(1783) = 4.542, p <.001. 2) Equal Variances NOT Assumed t(342.79) = 3.991. The large N has created a statistically significance difference out of a trivial difference; furthermore, the variances between the groups are statistically different. Can Levene's result be ignored because of the large sample or is it recommended that I report t test #2? I would appreciate any suggestions and, if possible, references on this problem. I thank you in advance. Stephen Salbod, Pace University NOTICE: This e-mail (and any attachments) may contain PRIVILEGED OR CONFIDENTIAL information and is intended only for the use of the specific individual(s) to whom it is addressed. It may contain information that is privileged and confidential under state and federal law. This information may be used or disclosed only in accordance with law, and you may be subject to penalties under law for improper use or further disclosure of the information in this e-mail and its attachments. If you have received this e-mail in error, please immediately notify the person named above by reply e-mail, and then delete the original e-mail. Thank you. |
In reply to this post by Salbod
I would recommend using the separate variances estimate to report.
The observed difference is not not readily attributable to random variation among samples from a common pop. i.e. the difference is "statistically significant". However, you characterize the difference as trivial, this should also be reported. It is difficult to comment further without more information about the study design, definitions of the DV and IV, and the decision this analysis was dine in support of. Art Kendall Social Research Consultants Stephen Salbod wrote: > Good Evening Everyone, > > > > I hope someone will guide me around this simple problem that fell in front > of me today. > > > > Which t test do I want to report? > > > > I have two groups: > > > > Group1 n= 1,512 M=2.5668 SD1=.80339 > > Group2 n= 273 M=2.3187 SD2=.96877 > > > > Levene's Test for Equality of Variance F= 27.531, p<.0001. > > > > 1) Equal Variances Assumed t(1783) = 4.542, p <.001. > > > > 2) Equal Variances NOT Assumed t(342.79) = 3.991. > > > > > > The large N has created a statistically significance difference out of a > trivial difference; furthermore, the variances between the groups are > statistically different. > > Can Levene's result be ignored because of the large sample or is it > recommended that I report t test #2? > > > > I would appreciate any suggestions and, if possible, references on this > problem. > > > > I thank you in advance. > > > > Stephen Salbod, Pace University > > >
Art Kendall
Social Research Consultants |
In reply to this post by Salbod
At 06:03 PM 3/23/2007, Stephen Salbod wrote:
>Which t test do I want to report? > >I have two groups: > >Group1 n= 1,512 M=2.5668 SD1=.80339 >Group2 n= 273 M=2.3187 SD2=.96877 > >Levene's Test for Equality of Variance F= 27.531, p<.0001. > >1) Equal Variances Assumed t(1783) = 4.542, p <.001. >2) Equal Variances NOT Assumed t(342.79) = 3.991. > >Can Levene's result be ignored because of the large sample or is it >recommended that I report t test #2? As others have noted, the simplest answer is, the test says different variances, you test assuming different variances. So far, so good, especially as it doesn't change anything of note. Now, you wrote, >The large N has created a statistically significance difference out of >a trivial difference That's the more interesting thing going on here: N is large enough that the old-school 'whether' test (i.e., for a significant difference) needs to be replaced by 'how much' tests (i.e., confidence intervals). Perhaps something like that should be done regarding Levene's test: variances within a certain ratio of each other may be treated as equal, even if 'significantly' different. In any case, simply reporting the t-test isn't illuminating, for the same reason. More like the following (based on generated data whose population parameters match the estimates you posted): a. Yes, the between-groups effect is strongly significant (p<.001) b. However, that is not much of the observed variance (R^2=.011) c. The best estimate of the difference between groups is .242 (95% CI, .137 to .346). Whether that's of practical significance, depends on the study. SPSS 15 draft output, heavily edited to shorten lines: UNIANOVA OBSERVE BY GROUP /METHOD = SSTYPE(3) /INTERCEPT = INCLUDE /PRINT = DESCRIPTIVE OPOWER PARAMETER HOMOGENEITY /CRITERIA = ALPHA(.05) /DESIGN = GROUP . Univariate Analysis of Variance |-----------------------------|---------------------------| |Output Created |26-MAR-2007 18:27:30 | |-----------------------------|---------------------------| [Salbod] Between-Subjects Factors [suppressed - see descriptives] Descriptive Statistics Dependent Variable: OBSERVE |-----|------|--------------|----| |GROUP|Mean |Std. Deviation|N | |-----|------|--------------|----| |1 |2.5724|.77670 |1512| |2 |2.3308|.96286 |273 | |-----|------|--------------|----| |Total|2.5355|.81232 |1785| |-----|------|--------------|----| Levene's Test of Equality of Error Variances(a) Dependent Variable: OBSERVE |------|---|----|----| |F |df1|df2 |Sig.| |------|---|----|----| |18.996|1 |1783|.000| |------|---|----|----| Tests the null hypothesis that the error variance of the dependent variable is equal across groups. a Design: Intercept+GROUP Tests of Between-Subjects Effects Dependent Variable: OBSERVE |----------|-----------|----|--------|--------|----|--------|---------| |Source |Type III |df |Mean |F |Sig.|Noncent.|Observed | | |Sum of | |Square | | |Param. |Power(a) | | |Squares | | | | | | | |----------|-----------|----|--------|--------|----|--------|---------| |Corrected |13.498(b) |1 |13.498 |20.682 |.000|20.682 |.995 | |Model | | | | | | | | |----------|-----------|----|--------|--------|----|--------|---------| |Intercept |5559.515 |1 |5559.515|8518.133|.000|8518.133|1.000 | |----------|-----------|----|--------|--------|----|--------|---------| |GROUP |13.498 |1 |13.498 |20.682 |.000|20.682 |.995 | |----------|-----------|----|--------|--------|----|--------|---------| |Error |1163.707 |1783|.653 | | | | | |----------|-----------|----|--------|--------|----|--------|---------| |Total |12652.135 |1785| | | | | | |----------|-----------|----|--------|--------|----|--------|---------| |Corrected |1177.206 |1784| | | | | | |Total | | | | | | | | |----------|-----------|----|--------|--------|----|--------|---------| a Computed using alpha = .05 b R Squared = .011 (Adjusted R Squared = .011) Parameter Estimates Dependent Variable: OBSERVE |---------|-----------|------|-------|------|----------------|----------|---------| |Parameter|B |Std. |t |Sig. |95% Confidence |Noncent. |Observed | | | |Error | | |Interval |Parameter |Power(a) | | |-----------|------|-------|------|--------|-------|----------|---------| | | | | | |Lower |Upper | | | | | | | | |Bound |Bound | | | |---------|-----------|------|-------|------|--------|-------|----------|---------| |Intercept|2.331 |.049 |47.669 |.000 |2.235 |2.427 |47.669 |1.000 | |---------|-----------|------|-------|------|--------|-------|----------|---------| |[GROUP=1]|.242 |.053 |4.548 |.000 |.137 |.346 |4.548 |.995 | |---------|-----------|------|-------|------|--------|-------|----------|---------| |[GROUP=2]|0(b) |. |. |. |. |. |. |. | |---------|-----------|------|-------|------|--------|-------|----------|---------| a Computed using alpha = .05 b This parameter is set to zero because it is redundant. =================== APPENDIX: Test data =================== Since this is randomly-generated data, a separate run will generally yield somewhat different results. Yeah, I could have put in a SET SEED. NEW FILE. INPUT PROGRAM. . NUMERIC SAMPLE (F3) /GROUP (F2) /OBSERVE (F5.2). . LEAVE SAMPLE GROUP. * Characteristics of the generated sample ......... . . COMPUTE #N1 = 1512 /* N, group 1 */. . COMPUTE #MEAN1 = 2.5668 /* Mean, group 1 */. . COMPUTE #SD1 = .80339 /* Std dev., group 1 */. . COMPUTE #N2 = 273 /* N, group 2 */. . COMPUTE #MEAN2 = 2.3187 /* Mean, group 2 */. . COMPUTE #SD2 = .96877 /* Std dev., group 2 */. . LOOP SAMPLE = 1 TO 1. . COMPUTE GROUP = 1. . LOOP #OBSNUM = 1 TO #N1. . COMPUTE OBSERVE = RV.NORMAL(#MEAN1,#SD1). . END CASE. . END LOOP. . COMPUTE GROUP = 2. . LOOP #OBSNUM = 1 TO #N2. . COMPUTE OBSERVE = RV.NORMAL(#MEAN2,#SD2). . END CASE. . END LOOP. . END LOOP. END FILE. END INPUT PROGRAM. DATASET NAME Salbod WINDOW=Front. |
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