Question about Chi-Square Output

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Question about Chi-Square Output

Jay Deitchman
Greetings,
 
I have some questions regarding the Chi-Square output below:
 
 

Chi-Square Tests

Value

df

Asymp. Sig. (2-sided)

Pearson Chi-Square

2.416(a)

3

.491

Likelihood Ratio

2.443

3

.486

Linear-by-Linear Association

.993

1

.319

N of Valid Cases

98

a 1 cells (12.5%) have expected count less than 5. The minimum expected count is 4.83.

Symmetric Measures

Value

Asymp. Std. Error(a)

Approx. T(b)

Approx. Sig.

Interval by Interval

Pearson's R

-.101

.101

-.997

.321(c)

Ordinal by Ordinal

Spearman Correlation

-.086

.102

-.845

.400(c)

N of Valid Cases

98

a Not assuming the null hypothesis.

b Using the asymptotic standard error assuming the null hypothesis.

c Based on normal approximation.

Q1. This may sound foolish, but am I correct that the p-value is -.101?
 
Q2. If the p-value is -.101, why is it negative/what does that mean?
 
In advance, any assistance is appreciated.
 
Thanks,
Jay

 

--
Mr. Jay B. Deitchman, M.S. Ed. Doctoral Candidate, University at Albany
(Cell) 607.267.9447 (Home) 607.638.1909 (Office) 518.629.7567 [hidden email]
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Re: Question about Chi-Square Output

Swank, Paul R

That is the r, not the p value. The p value for that r is .321.

 

Dr. Paul R. Swank,

Professor and Director of Research

Children's Learning Institute

University of Texas Health Science Center-Houston

 

From: SPSSX(r) Discussion [mailto:[hidden email]] On Behalf Of Jay Deitchman
Sent: Friday, June 26, 2009 5:24 PM
To: [hidden email]
Subject: Question about Chi-Square Output

 

Greetings,

 

I have some questions regarding the Chi-Square output below:

 

 

Chi-Square Tests

Value

df

Asymp. Sig. (2-sided)

Pearson Chi-Square

2.416(a)

3

.491

Likelihood Ratio

2.443

3

.486

Linear-by-Linear Association

.993

1

.319

N of Valid Cases

98

a 1 cells (12.5%) have expected count less than 5. The minimum expected count is 4.83.

Symmetric Measures

Value

Asymp. Std. Error(a)

Approx. T(b)

Approx. Sig.

Interval by Interval

Pearson's R

-.101

.101

-.997

.321(c)

Ordinal by Ordinal

Spearman Correlation

-.086

.102

-.845

.400(c)

N of Valid Cases

98

a Not assuming the null hypothesis.

b Using the asymptotic standard error assuming the null hypothesis.

c Based on normal approximation.

Q1. This may sound foolish, but am I correct that the p-value is -.101?

 

Q2. If the p-value is -.101, why is it negative/what does that mean?

 

In advance, any assistance is appreciated.

 

Thanks,

Jay


 


--
Mr. Jay B. Deitchman, M.S. Ed. Doctoral Candidate, University at Albany
(Cell) 607.267.9447 (Home) 607.638.1909 (Office) 518.629.7567 [hidden email]