SPSS macro does not process list correct

[Thomas Lindner]

Dear SPSS-users,

I try to create some new filter variables using a macro (using SPSS 15.0.1 on WindowsXP pro).

               DEFINE !probe1 (zet=!ENCLOSE('(',')' ))
                !Do !i !IN (!zet)
                compute !concat(filter, !zet) = 0 .
                !DOEND
                EXECUTE .
        !ENDDEFINE .

        !probe1 zet=  (b c) .

As long as I use the macro with only one element within the list it works fine. But if I use more than one elements I get an error message (see output of the log at the end).

The elements (b and c) of the list (zet) may not recognised as single elements. They are used as "b c".
(output row 173, 174)

I appreciate any advise helping to solve this problem.

Thank you in advance.

Thomas Lindner



output from log:


 164 M>  DEFINE
 165 M>   !Probe1 (zet=!ENCLOSE('(',')' ))
 166 M>   !Do !i !IN (!zet)
 167 M>   compute !concat(filter, !zet) = 0 .
 168 M>   !DOEND
 169 M>   EXECUTE .
 170 M>   !ENDDEFINE .

!Probe1 zet=  (b c) .
 171 M>
 172 M>  .
 173 M>  compute filterb c = 0.

>Error # 4382 in column 17.  Text: c
>An equals sign was not found when expected after a target variable in a
>COMPUTE command.
>This command not executed.

 174 M>  compute filterb c = 0.

>Error # 4382 in column 17.  Text: c
>An equals sign was not found when expected after a target variable in a
>COMPUTE command.
>This command not executed.

 175 M>  EXECUTE
 176 M>  .

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[Melissa Ives]

For George....

By the way, I tried again and got the same "You are spam" message. Double unhappy here. My test goes fine but my answer doesn't.
Here is my message:

"Trying again!

Hi Thomas,
Use
compute !concat(filter, !I) = 0 .

instead of
compute !concat(filter, !zet) = 0 .

Regards,
George"

Regards,
George


Melissa

-----Original Message-----
From: SPSSX(r) Discussion [mailto:[hidden email]] On Behalf Of Thomas Lindner
Sent: Thursday, October 16, 2008 5:08 AM
To: [hidden email]
Subject: [SPSSX-L] SPSS macro does not process list correct

Dear SPSS-users,

I try to create some new filter variables using a macro (using SPSS 15.0.1 on WindowsXP pro).

               DEFINE !probe1 (zet=!ENCLOSE('(',')' ))
                !Do !i !IN (!zet)
                compute !concat(filter, !zet) = 0 .
                !DOEND
                EXECUTE .
        !ENDDEFINE .

        !probe1 zet=  (b c) .

As long as I use the macro with only one element within the list it works fine. But if I use more than one elements I get an error message (see output of the log at the end).

The elements (b and c) of the list (zet) may not recognised as single elements. They are used as "b c".
(output row 173, 174)

I appreciate any advise helping to solve this problem.

Thank you in advance.

Thomas Lindner



output from log:


 164 M>  DEFINE
 165 M>   !Probe1 (zet=!ENCLOSE('(',')' ))
 166 M>   !Do !i !IN (!zet)
 167 M>   compute !concat(filter, !zet) = 0 .
 168 M>   !DOEND
 169 M>   EXECUTE .
 170 M>   !ENDDEFINE .

!Probe1 zet=  (b c) .
 171 M>
 172 M>  .
 173 M>  compute filterb c = 0.

>Error # 4382 in column 17.  Text: c
>An equals sign was not found when expected after a target variable in a
>COMPUTE command.
>This command not executed.

 174 M>  compute filterb c = 0.

>Error # 4382 in column 17.  Text: c
>An equals sign was not found when expected after a target variable in a
>COMPUTE command.
>This command not executed.

 175 M>  EXECUTE
 176 M>  .

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