Unequal bin size in histograms

[Robert L]

I have got this material where it would be very convenient to describe the age distribution with varying bin sizes. Thinner intervals for the major part of the material, and broader bins for especially the higher ages. Is there any way to do this in SPSS?

Robert

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[Art Kendall]

<transformation> <visual binning> .... <paste>
<transformation> <optimal binning> ... <paste>

RANK ... /ntiles= ...
On 10/21/2013 5:33 AM, Robert Lundqvist-3 [via SPSSX Discussion] wrote:

I have got this material where it would be very convenient to describe the age distribution with varying bin sizes. Thinner intervals for the major part of the material, and broader bins for especially the higher ages. Is there any way to do this in SPSS?

Robert

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[Andy W]

Here is an example in GPL how I would go about doing this in addition to Art's advice. As long as you can make data of the form

begin fence - end fence - height

You can use GPL to draw the boxes. I did a similar trick here, http://andrewpwheeler.wordpress.com/2013/04/21/spineplots-in-spss/. It shouldn't be too arduous a programming exercise to whip the data into that shape (but I am unfamiliar with automatic algorithms to produce unequal bin width histograms).

***************************************************************.
data list free / beginX endX height.
begin data
0 5 5
5 15 10
15 30 15
30 31 3
end data.
dataset name unequalHist.
formats all (F2.0).

*Uneqal Histogram with Polygons.
GGRAPH
  /GRAPHDATASET NAME="graphdataset" VARIABLES=beginX endX height
  /GRAPHSPEC SOURCE=INLINE.
BEGIN GPL
 SOURCE: s=userSource(id("graphdataset"))
 DATA: beginX=col(source(s), name("beginX"))
 DATA: endX=col(source(s), name("endX"))
 DATA: height=col(source(s), name("height"))
 TRANS: base=eval(0)
 TRANS: casenum = index()
 GUIDE: axis(dim(1), label("X"))
 GUIDE: axis(dim(2), label("Freq."))
 ELEMENT: polygon(position(link.hull((beginX + endX)*(base + height))), color.interior(color.grey), split(casenum))
END GPL.
***************************************************************.

[John F Hall]

You can also use RECODE in syntax (substitute your own ranges):

 

This might come in handy first:

 

FREQ oldvar /for not/ per 10 20 30 40 50 60 70 80 90 /his.

 

. . suppresses frequency table, gives deciles (but you can use any quantiles you like and a histogram (if your data are ordinal use /bar instead).

 

 

RECODE oldvar (value1 thru value2 = 1)(value3 thru value4=2 )(value5 thru value6 = 3)

~ ~ ~ etc etc

INTO newvar.

 

 

 

 

From: SPSSX(r) Discussion [mailto:[hidden email]] On Behalf Of Art Kendall
Sent: 21 October 2013 13:28
To: [hidden email]
Subject: Re: Unequal bin size in histograms

 

<transformation> <visual binning> .... <paste>
<transformation> <optimal binning> ... <paste>

RANK ... /ntiles= ...

Art Kendall

Social Research Consultants

On 10/21/2013 5:33 AM, Robert Lundqvist-3 [via SPSSX Discussion] wrote:

I have got this material where it would be very convenient to describe the age distribution with varying bin sizes. Thinner intervals for the major part of the material, and broader bins for especially the higher ages. Is there any way to do this in SPSS?

Robert

=====================
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Art Kendall
Social Research Consultants

 

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