python: if and if statements
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how can I cut short lots of "if and if ..."-Statements in python (all statements have to be ==1). Example:
if len(alpha) ==1 and len(beta1) ==1 and len(beta2) ==1 and len(alpha_stdfehler) ==1 and len(beta1_stdfehler) ==1 and len(beta2_stdfehler) ==1 and len(alpha_T)==1 and len(beta1_T)==1 and len(beta2_T)==1 and len(r_quadrat)==1 and len(r_quadrat_stdfehler)==1 : -> if any(alpha, beta, ....) <> 1 continue else: ... something like that? Couldn't find a solution. Thanks
Dr. Frank Gaeth
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Re: python: if and if statements
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How about
1 not in [len(alpha), len(beta), len(beta2) ...] Garry Gelade -----Original Message----- From: SPSSX(r) Discussion [mailto:[hidden email]] On Behalf Of drfg2008 Sent: 08 June 2011 08:12 To: [hidden email] Subject: python: if and if statements how can I cut short lots of "if and if ..."-Statements in python (all statements have to be ==1). Example: if len(alpha) ==1 and len(beta1) ==1 and len(beta2) ==1 and len(alpha_stdfehler) ==1 and len(beta1_stdfehler) ==1 and len(beta2_stdfehler) ==1 and len(alpha_T)==1 and len(beta1_T)==1 and len(beta2_T)==1 and len(r_quadrat)==1 and len(r_quadrat_stdfehler)==1 : -> if any(alpha, beta, ....) <> 1 continue else: ... something like that? Couldn't find a solution. Thanks ----- Dr. Frank Gaeth FU-Berlin -- View this message in context: http://spssx-discussion.1045642.n5.nabble.com/python-if-and-if-statements-tp 4467945p4467945.html Sent from the SPSSX Discussion mailing list archive at Nabble.com. ===================== To manage your subscription to SPSSX-L, send a message to [hidden email] (not to SPSSX-L), with no body text except the command. To leave the list, send the command SIGNOFF SPSSX-L For a list of commands to manage subscriptions, send the command INFO REFCARD ===================== To manage your subscription to SPSSX-L, send a message to [hidden email] (not to SPSSX-L), with no body text except the command. To leave the list, send the command SIGNOFF SPSSX-L For a list of commands to manage subscriptions, send the command INFO REFCARD |
Re: python: if and if statements
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In reply to this post by drfg2008
http://docs.python.org/library/functions.html#all
>>> x = y = 2; z = 1 >>> [i != 1 for i in [x, y, z]] [True, True, False] >>> all([i != 1 for i in [x, y, z]]) False Albert-Jan ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
All right, but apart from the sanitation, the medicine, education, wine, public order, irrigation, roads, a fresh water system, and public health, what have the Romans ever done for us? ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ From: drfg2008 <[hidden email]> To: [hidden email] Sent: Wed, June 8, 2011 9:12:00 AM Subject: [SPSSX-L] python: if and if statements how can I cut short lots of "if and if ..."-Statements in python (all statements have to be ==1). Example: if len(alpha) ==1 and len(beta1) ==1 and len(beta2) ==1 and len(alpha_stdfehler) ==1 and len(beta1_stdfehler) ==1 and len(beta2_stdfehler) ==1 and len(alpha_T)==1 and len(beta1_T)==1 and len(beta2_T)==1 and len(r_quadrat)==1 and len(r_quadrat_stdfehler)==1 : -> if any(alpha, beta, ....) <> 1 continue else: ... something like that? Couldn't find a solution. Thanks ----- Dr. Frank Gaeth FU-Berlin -- View this message in context: http://spssx-discussion.1045642.n5.nabble.com/python-if-and-if-statements-tp4467945p4467945.html Sent from the SPSSX Discussion mailing list archive at Nabble.com. ===================== To manage your subscription to SPSSX-L, send a message to [hidden email] (not to SPSSX-L), with no body text except the command. To leave the list, send the command SIGNOFF SPSSX-L For a list of commands to manage subscriptions, send the command INFO REFCARD |
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In reply to this post by drfg2008
Lots of ways to do this. Here's one
more
if min(a,b,c) == max(a,b,c) == 1: ... IIRC, the original logic was just that these values not be 0, so you could simplify further to if min(a,b,c): ... since 0 is False Jon Peck Senior Software Engineer, IBM [hidden email] new phone: 720-342-5621 From: drfg2008 <[hidden email]> To: [hidden email] Date: 06/08/2011 01:17 AM Subject: [SPSSX-L] python: if and if statements Sent by: "SPSSX(r) Discussion" <[hidden email]> how can I cut short lots of "if and if ..."-Statements in python (all statements have to be ==1). Example: if len(alpha) ==1 and len(beta1) ==1 and len(beta2) ==1 and len(alpha_stdfehler) ==1 and len(beta1_stdfehler) ==1 and len(beta2_stdfehler) ==1 and len(alpha_T)==1 and len(beta1_T)==1 and len(beta2_T)==1 and len(r_quadrat)==1 and len(r_quadrat_stdfehler)==1 : -> if any(alpha, beta, ....) <> 1 continue else: ... something like that? Couldn't find a solution. Thanks ----- Dr. Frank Gaeth FU-Berlin -- View this message in context: http://spssx-discussion.1045642.n5.nabble.com/python-if-and-if-statements-tp4467945p4467945.html Sent from the SPSSX Discussion mailing list archive at Nabble.com. ===================== To manage your subscription to SPSSX-L, send a message to [hidden email] (not to SPSSX-L), with no body text except the command. To leave the list, send the command SIGNOFF SPSSX-L For a list of commands to manage subscriptions, send the command INFO REFCARD |
Re: python: if and if statements
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Probably a bit too much, but I just like map & lambda functions:  Assuming the vars are strings:  alpha = 't'
beta = 'e' beta2 = 's' alpha_stdfehler = 't' Â aList = [alpha, beta, beta2, alpha_stdfehler] Â allOneLenght = sum(list(map(lambda x: len(x) == 1, aList))) == len(aList) if allOneLenght: Â Â Â Â Â Â Â Â Â Â Â Â
Hope this help (but I doubt that...),  Edwin Meijdam On Wed, Jun 8, 2011 at 2:42 PM, Jon K Peck <[hidden email]> wrote: Lots of ways to do this.  Here's one more -- Edwin Meijdam +31(0)6 159 608 37 DASC B.V. |
Re: python: if and if statements
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Hmm, I like this better:
>>> all([len(alpha)==1, len(beta)==1, len(beta2)==1, len(alpha_stdfehler)==1]) True But you're right, lambdas rock: >>> all([filter(lambda arg: len(arg)==1, [alpha, beta, beta2, alpha_stdfehler])]) True Albert-Jan ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
All right, but apart from the sanitation, the medicine, education, wine, public order, irrigation, roads, a fresh water system, and public health, what have the Romans ever done for us? ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ From: Edwin Meijdam <[hidden email]> To: [hidden email] Sent: Wed, June 8, 2011 3:29:01 PM Subject: Re: [SPSSX-L] python: if and if statements Probably a bit too much, but I just like map & lambda functions: Assuming the vars are strings: alpha = 't'
beta = 'e' beta2 = 's' alpha_stdfehler = 't' aList = [alpha, beta, beta2, alpha_stdfehler] allOneLenght = sum(list(map(lambda x: len(x) == 1, aList))) == len(aList) if allOneLenght: Hope this help (but I doubt that...), Edwin Meijdam On Wed, Jun 8, 2011 at 2:42 PM, Jon K Peck <[hidden email]> wrote: Lots of ways to do this. Here's one more -- Edwin Meijdam +31(0)6 159 608 37 DASC B.V. |
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No need for lambda here or filter - and,
BTW, lambda barely escaped elimination in Python 3.
All you need is a list comprehension. all([len(item) == 1 for item in [a,b,c]]) Jon Peck Senior Software Engineer, IBM [hidden email] new phone: 720-342-5621 From: Albert-Jan Roskam <[hidden email]> To: [hidden email] Date: 06/08/2011 10:03 AM Subject: Re: [SPSSX-L] python: if and if statements Sent by: "SPSSX(r) Discussion" <[hidden email]> Hmm, I like this better: >>> all([len(alpha)==1, len(beta)==1, len(beta2)==1, len(alpha_stdfehler)==1]) True But you're right, lambdas rock: >>> all([filter(lambda arg: len(arg)==1, [alpha, beta, beta2, alpha_stdfehler])]) True Cheers!! Albert-Jan ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ All right, but apart from the sanitation, the medicine, education, wine, public order, irrigation, roads, a fresh water system, and public health, what have the Romans ever done for us? ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ From: Edwin Meijdam <[hidden email]> To: [hidden email] Sent: Wed, June 8, 2011 3:29:01 PM Subject: Re: [SPSSX-L] python: if and if statements Probably a bit too much, but I just like map & lambda functions: Assuming the vars are strings: alpha = 't' beta = 'e' beta2 = 's' alpha_stdfehler = 't' aList = [alpha, beta, beta2, alpha_stdfehler] allOneLenght = sum(list(map(lambda x: len(x) == 1, aList))) == len(aList) if allOneLenght: Hope this help (but I doubt that...), Edwin Meijdam On Wed, Jun 8, 2011 at 2:42 PM, Jon K Peck <peck@...> wrote: Lots of ways to do this. Here's one more if min(a,b,c) == max(a,b,c) == 1: ... IIRC, the original logic was just that these values not be 0, so you could simplify further to if min(a,b,c): ... since 0 is False Jon Peck Senior Software Engineer, IBM peck@... new phone: 720-342-5621 From: drfg2008 <kontakt@...> To: [hidden email] Date: 06/08/2011 01:17 AM Subject: [SPSSX-L] python: if and if statements Sent by: "SPSSX(r) Discussion" <[hidden email]> how can I cut short lots of "if and if ..."-Statements in python (all statements have to be ==1). Example: if len(alpha) ==1 and len(beta1) ==1 and len(beta2) ==1 and len(alpha_stdfehler) ==1 and len(beta1_stdfehler) ==1 and len(beta2_stdfehler) ==1 and len(alpha_T)==1 and len(beta1_T)==1 and len(beta2_T)==1 and len(r_quadrat)==1 and len(r_quadrat_stdfehler)==1 : -> if any(alpha, beta, ....) <> 1 continue else: ... something like that? Couldn't find a solution. Thanks ----- Dr. Frank Gaeth FU-Berlin -- View this message in context: http://spssx-discussion.1045642.n5.nabble.com/python-if-and-if-statements-tp4467945p4467945.html Sent from the SPSSX Discussion mailing list archive at Nabble.com. ===================== To manage your subscription to SPSSX-L, send a message to LISTSERV@... (not to SPSSX-L), with no body text except the command. To leave the list, send the command SIGNOFF SPSSX-L For a list of commands to manage subscriptions, send the command INFO REFCARD -- Edwin Meijdam +31(0)6 159 608 37 DASC B.V. Postbus 88 4130 EB Vianen 085 - 8774406 emeijdam@... http://www.linkedin.com/in/emeijdam |
Re: python: if and if statements
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That's an even nicer notation. Yes, I've heard that many people are not fans of lambda, or of map, filter, reduce. Lambda is nice and compact but I could live with just normal def functions. I find it useful, though, to pass an argument to an event handler, but now that I have looked up an example I see that there are alternatives: http://stackoverflow.com/questions/3296893/how-to-pass-an-argument-to-event-handler-python-tkinter-programming (I meant the second solution)
I read somewhere that loops could be faster when map is used, compared to a simple for loop, because the code 'is pushed straight into C'. Is that true? In R it certainly is (*apply vs. for) but in Python..? Albert-Jan ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
All right, but apart from the sanitation, the medicine, education, wine, public order, irrigation, roads, a fresh water system, and public health, what have the Romans ever done for us? ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ From: Jon K Peck <[hidden email]> To: [hidden email] Sent: Wed, June 8, 2011 6:09:57 PM Subject: Re: [SPSSX-L] python: if and if statements No need for lambda here or filter - and, BTW, lambda barely escaped elimination in Python 3. All you need is a list comprehension. all([len(item) == 1 for item in [a,b,c]]) Jon Peck Senior Software Engineer, IBM [hidden email] new phone: 720-342-5621 From: Albert-Jan Roskam <[hidden email]> To: [hidden email] Date: 06/08/2011 10:03 AM Subject: Re: [SPSSX-L] python: if and if statements Sent by: "SPSSX(r) Discussion" <[hidden email]> Hmm, I like this better: >>> all([len(alpha)==1, len(beta)==1, len(beta2)==1, len(alpha_stdfehler)==1]) True But you're right, lambdas rock: >>> all([filter(lambda arg: len(arg)==1, [alpha, beta, beta2, alpha_stdfehler])]) True Cheers!! Albert-Jan ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ All right, but apart from the sanitation, the medicine, education, wine, public order, irrigation, roads, a fresh water system, and public health, what have the Romans ever done for us? ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ From: Edwin Meijdam <[hidden email]> To: [hidden email] Sent: Wed, June 8, 2011 3:29:01 PM Subject: Re: [SPSSX-L] python: if and if statements Probably a bit too much, but I just like map & lambda functions: Assuming the vars are strings: alpha = 't' beta = 'e' beta2 = 's' alpha_stdfehler = 't' aList = [alpha, beta, beta2, alpha_stdfehler] allOneLenght = sum(list(map(lambda x: len(x) == 1, aList))) == len(aList) if allOneLenght: Hope this help (but I doubt that...), Edwin Meijdam On Wed, Jun 8, 2011 at 2:42 PM, Jon K Peck <[hidden email]> wrote: Lots of ways to do this. Here's one more if min(a,b,c) == max(a,b,c) == 1: ... IIRC, the original logic was just that these values not be 0, so you could simplify further to if min(a,b,c): ... since 0 is False Jon Peck Senior Software Engineer, IBM [hidden email] new phone: 720-342-5621 From: drfg2008 <[hidden email]> To: [hidden email] Date: 06/08/2011 01:17 AM Subject: [SPSSX-L] python: if and if statements Sent by: "SPSSX(r) Discussion" <[hidden email]> how can I cut short lots of "if and if ..."-Statements in python (all statements have to be ==1). Example: if len(alpha) ==1 and len(beta1) ==1 and len(beta2) ==1 and len(alpha_stdfehler) ==1 and len(beta1_stdfehler) ==1 and len(beta2_stdfehler) ==1 and len(alpha_T)==1 and len(beta1_T)==1 and len(beta2_T)==1 and len(r_quadrat)==1 and len(r_quadrat_stdfehler)==1 : -> if any(alpha, beta, ....) <> 1 continue else: ... something like that? Couldn't find a solution. Thanks ----- Dr. Frank Gaeth FU-Berlin -- View this message in context: http://spssx-discussion.1045642.n5.nabble.com/python-if-and-if-statements-tp4467945p4467945.html Sent from the SPSSX Discussion mailing list archive at Nabble.com. ===================== To manage your subscription to SPSSX-L, send a message to [hidden email] (not to SPSSX-L), with no body text except the command. To leave the list, send the command SIGNOFF SPSSX-L For a list of commands to manage subscriptions, send the command INFO REFCARD -- Edwin Meijdam +31(0)6 159 608 37 DASC B.V. Postbus 88 4130 EB Vianen 085 - 8774406 [hidden email] http://www.linkedin.com/in/emeijdam |
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IMO, map, filter, et al are redundant and
no longer recommended. There are a few occasions where I still find
reduce useful. The list comprehension provides a general solution
that covers all of these. List comprehensions are more efficient
than explicit loops, too. They generate fewer virtual machine instructions.
R looping is notoriously slow, so using vectorized functions is always preferred there. I just wish that it didn't have so many different apply-like functions, since it is hard to keep them all straight (apply, sapply, mapply, lapply, tapply). That's a symptom of a badly designed language IMO. Jon Peck Senior Software Engineer, IBM [hidden email] new phone: 720-342-5621 From: Albert-Jan Roskam <[hidden email]> To: Jon K Peck/Chicago/IBM@IBMUS, [hidden email] Date: 06/08/2011 10:45 AM Subject: Re: [SPSSX-L] python: if and if statements That's an even nicer notation. Yes, I've heard that many people are not fans of lambda, or of map, filter, reduce. Lambda is nice and compact but I could live with just normal def functions. I find it useful, though, to pass an argument to an event handler, but now that I have looked up an example I see that there are alternatives: http://stackoverflow.com/questions/3296893/how-to-pass-an-argument-to-event-handler-python-tkinter-programming (I meant the second solution) I read somewhere that loops could be faster when map is used, compared to a simple for loop, because the code 'is pushed straight into C'. Is that true? In R it certainly is (*apply vs. for) but in Python..? Cheers!! Albert-Jan ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ All right, but apart from the sanitation, the medicine, education, wine, public order, irrigation, roads, a fresh water system, and public health, what have the Romans ever done for us? ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ From: Jon K Peck <[hidden email]> To: [hidden email] Sent: Wed, June 8, 2011 6:09:57 PM Subject: Re: [SPSSX-L] python: if and if statements No need for lambda here or filter - and, BTW, lambda barely escaped elimination in Python 3. All you need is a list comprehension. all([len(item) == 1 for item in [a,b,c]]) Jon Peck Senior Software Engineer, IBM [hidden email] new phone: 720-342-5621 From: Albert-Jan Roskam <[hidden email]> To: [hidden email] Date: 06/08/2011 10:03 AM Subject: Re: [SPSSX-L] python: if and if statements Sent by: "SPSSX(r) Discussion" <[hidden email]> Hmm, I like this better: >>> all([len(alpha)==1, len(beta)==1, len(beta2)==1, len(alpha_stdfehler)==1]) True But you're right, lambdas rock: >>> all([filter(lambda arg: len(arg)==1, [alpha, beta, beta2, alpha_stdfehler])]) True Cheers!! Albert-Jan ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ All right, but apart from the sanitation, the medicine, education, wine, public order, irrigation, roads, a fresh water system, and public health, what have the Romans ever done for us? ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ From: Edwin Meijdam <[hidden email]> To: [hidden email] Sent: Wed, June 8, 2011 3:29:01 PM Subject: Re: [SPSSX-L] python: if and if statements Probably a bit too much, but I just like map & lambda functions: Assuming the vars are strings: alpha = 't' beta = 'e' beta2 = 's' alpha_stdfehler = 't' aList = [alpha, beta, beta2, alpha_stdfehler] allOneLenght = sum(list(map(lambda x: len(x) == 1, aList))) == len(aList) if allOneLenght: Hope this help (but I doubt that...), Edwin Meijdam On Wed, Jun 8, 2011 at 2:42 PM, Jon K Peck <peck@...> wrote: Lots of ways to do this. Here's one more if min(a,b,c) == max(a,b,c) == 1: ... IIRC, the original logic was just that these values not be 0, so you could simplify further to if min(a,b,c): ... since 0 is False Jon Peck Senior Software Engineer, IBM peck@... new phone: 720-342-5621 From: drfg2008 <kontakt@...> To: [hidden email] Date: 06/08/2011 01:17 AM Subject: [SPSSX-L] python: if and if statements Sent by: "SPSSX(r) Discussion" <[hidden email]> how can I cut short lots of "if and if ..."-Statements in python (all statements have to be ==1). Example: if len(alpha) ==1 and len(beta1) ==1 and len(beta2) ==1 and len(alpha_stdfehler) ==1 and len(beta1_stdfehler) ==1 and len(beta2_stdfehler) ==1 and len(alpha_T)==1 and len(beta1_T)==1 and len(beta2_T)==1 and len(r_quadrat)==1 and len(r_quadrat_stdfehler)==1 : -> if any(alpha, beta, ....) <> 1 continue else: ... something like that? Couldn't find a solution. Thanks ----- Dr. Frank Gaeth FU-Berlin -- View this message in context: http://spssx-discussion.1045642.n5.nabble.com/python-if-and-if-statements-tp4467945p4467945.html Sent from the SPSSX Discussion mailing list archive at Nabble.com. ===================== To manage your subscription to SPSSX-L, send a message to LISTSERV@... (not to SPSSX-L), with no body text except the command. To leave the list, send the command SIGNOFF SPSSX-L For a list of commands to manage subscriptions, send the command INFO REFCARD -- Edwin Meijdam +31(0)6 159 608 37 DASC B.V. Postbus 88 4130 EB Vianen 085 - 8774406 emeijdam@... http://www.linkedin.com/in/emeijdam |
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In reply to this post by Jon K Peck
Thanks everyone for your help.
However, for a python-starter like me there is a little problem with: all([len(item) == 1 for item in [a,b,c]]) I tried: if all([len(item) == 1 for item in [alpha,beta1,beta2]): .... code all([len(item) == 1 for item in [alpha,beta1,beta2]): .... code all([len(item) == 1 for item in [alpha,beta1,beta2]) .... code no success. I checked list comprehensions in python, but couldn't find a similar case so far. Thanks for help.
Dr. Frank Gaeth
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Re: python: if and if statements
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You'll usually find a list comprehension in something like the following form
items = [a,b,c]
[len(item) == 1 for item in items] # the list comprehension The part "len(item) == 1" is evaluated for each item, and evaluates to True or False.
The resulting lists consists of Booleans, which are given to the all() function. If all the booleans in the lists are True, all() returns True, else it returns False.
So if you subdivide the one-liner into two or three steps, the code is easier to understand. It also allows you to insert some print statements to see what's going on.
Albert-Jan ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ All right, but apart from the sanitation, the medicine, education, wine, public order, irrigation, roads, a fresh water system, and public health, what have the Romans ever done for us? ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ From: drfg2008 <[hidden email]> To: [hidden email] Sent: Thu, June 9, 2011 10:01:26 AM Subject: Re: [SPSSX-L] python: if and if statements Thanks everyone for your help. However, for a python-starter like me there is a little problem with: all([len(item) == 1 for item in [a,b,c]]) I tried: if all([len(item) == 1 for item in [alpha,beta1,beta2]): .... code all([len(item) == 1 for item in [alpha,beta1,beta2]): .... code all([len(item) == 1 for item in [alpha,beta1,beta2]) .... code no success. I checked list comprehensions in python, but couldn't find a similar case so far. Thanks for help. ----- Dr. Frank Gaeth FU-Berlin -- View this message in context: http://spssx-discussion.1045642.n5.nabble.com/python-if-and-if-statements-tp4467945p4471929.html Sent from the SPSSX Discussion mailing list archive at Nabble.com. ===================== To manage your subscription to SPSSX-L, send a message to [hidden email] (not to SPSSX-L), with no body text except the command. To leave the list, send the command SIGNOFF SPSSX-L For a list of commands to manage subscriptions, send the command INFO REFCARD |
Re: python: if and if statements
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In reply to this post by drfg2008
You have unbalanced square brackets in your example.
Garry Gelade -----Original Message----- From: SPSSX(r) Discussion [mailto:[hidden email]] On Behalf Of drfg2008 Sent: 09 June 2011 09:01 To: [hidden email] Subject: Re: python: if and if statements Thanks everyone for your help. However, for a python-starter like me there is a little problem with: all([len(item) == 1 for item in [a,b,c]]) I tried: if all([len(item) == 1 for item in [alpha,beta1,beta2]): .... code all([len(item) == 1 for item in [alpha,beta1,beta2]): .... code all([len(item) == 1 for item in [alpha,beta1,beta2]) .... code no success. I checked list comprehensions in python, but couldn't find a similar case so far. Thanks for help. ----- Dr. Frank Gaeth FU-Berlin -- View this message in context: http://spssx-discussion.1045642.n5.nabble.com/python-if-and-if-statements-tp 4467945p4471929.html Sent from the SPSSX Discussion mailing list archive at Nabble.com. ===================== To manage your subscription to SPSSX-L, send a message to [hidden email] (not to SPSSX-L), with no body text except the command. To leave the list, send the command SIGNOFF SPSSX-L For a list of commands to manage subscriptions, send the command INFO REFCARD ===================== To manage your subscription to SPSSX-L, send a message to [hidden email] (not to SPSSX-L), with no body text except the command. To leave the list, send the command SIGNOFF SPSSX-L For a list of commands to manage subscriptions, send the command INFO REFCARD |
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