question about number of years applied
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question about number of years applied
 
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Hi all,
I feel like there must be a way to generate this variable, but have been spinning my wheels and can't come up with a solution. I have a dataset with department ID numbers, and each department has grant years for which they applied for a grant (denoted by year number). It's easier for me to show what the data looks like rather than trying to describe it: Dept. # 1st grant 2nd grant 3rd grant 4th grant 5th grant 1 2001 2001 2002 2002 2 2001 2002 2002 2002 3 2001 2001 2002 2002 2003 4 2002 2003 2004 2005 5 2004 2004 2005 2005 6 2001 2002 2003 2004 2005 7 2003 2004 2004 2004 I'd like to generate a variable that indicates the number of years that a department has applied for grants. For example, Dept. #1 has applied for 4 grants, but has only applied in 2 year, Dept. 4 has applied for 4 grants, but has applied in 4 years. This is how I'd like the new number of years variable to look: Dept. # years applied 1 2 2 2 3 3 4 4 5 2 6 5 7 2 If you have any idea of how I'd go about doing this, I would greatly appreciate your feedback! Thank you, Miriam Gerver |
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A little down and dirty, but this works.
meljr GET FILE='C:\SPSS Training\Vectors\agg_grants.sav'. COUNT V2001=grant1 grant2 grant3 grant4 grant5 (2001). COUNT V2002=grant1 grant2 grant3 grant4 grant5 (2002). COUNT V2003=grant1 grant2 grant3 grant4 grant5 (2003). COUNT V2004=grant1 grant2 grant3 grant4 grant5 (2004). COUNT V2005=grant1 grant2 grant3 grant4 grant5 (2005). if (v2001 >=1) v2001 = 1. if (v2002 >=1) v2002 = 1. if (v2003 >=1) v2003 = 1. if (v2004 >=1) v2004 = 1. if (v2005 >=1) v2005 = 1. compute yrs_ap = sum(v2001 to v2005). fre var = yrs_ap.
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Re: question about number of years applied
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In reply to this post by Miriam L. Gerver
Hi Miriam,
You can try the following syntax. Basically I did count years in the grant year and recode them to 1 and then count again. Some one in the list may come up with a concise way. DATA LIST free/ Dept(n1) grant1(n4) grant2(n4) grant3(n4) grant4(n4) grant5(n4). Begin data 1 2001 2001 2002 2002 0 2 2001 2002 2002 2002 0 3 2001 2001 2002 2002 2003 4 2002 2003 2004 2005 0 5 2004 2004 2005 2005 0 6 2001 2002 2003 2004 2005 7 2003 2004 2004 2004 0 End data. Execute. COUNT Y2001 = grant1 to grant5(2001). EXECUTE . COUNT Y2002 = grant1 to grant5(2002). EXECUTE . COUNT Y2003 = grant1 to grant5(2003). EXECUTE . COUNT Y2004 = grant1 to grant5(2004). EXECUTE . COUNT Y2005 = grant1 to grant5(2005). EXECUTE . RECODE Y2001 Y2002 Y2003 Y2004 Y2005 (1 thru Highest=1) . EXECUTE . COUNT Years_Applied = Y2001 to Y2005(1). EXECUTE . Thanks, Mahbub -----Original Message----- From: SPSSX(r) Discussion [mailto:[hidden email]] On Behalf Of Miriam L. Gerver Sent: 22-Mar-07 11:23 AM To: [hidden email] Subject: question about number of years applied Hi all, I feel like there must be a way to generate this variable, but have been spinning my wheels and can't come up with a solution. I have a dataset with department ID numbers, and each department has grant years for which they applied for a grant (denoted by year number). It's easier for me to show what the data looks like rather than trying to describe it: Dept. # 1st grant 2nd grant 3rd grant 4th grant 5th grant 1 2001 2001 2002 2002 2 2001 2002 2002 2002 3 2001 2001 2002 2002 2003 4 2002 2003 2004 2005 5 2004 2004 2005 2005 6 2001 2002 2003 2004 2005 7 2003 2004 2004 2004 I'd like to generate a variable that indicates the number of years that a department has applied for grants. For example, Dept. #1 has applied for 4 grants, but has only applied in 2 year, Dept. 4 has applied for 4 grants, but has applied in 4 years. This is how I'd like the new number of years variable to look: Dept. # years applied 1 2 2 2 3 3 4 4 5 2 6 5 7 2 If you have any idea of how I'd go about doing this, I would greatly appreciate your feedback! Thank you, Miriam Gerver |
Re: question about number of years applied
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In reply to this post by Miriam L. Gerver
At 11:23 AM 3/22/2007, Miriam L. Gerver wrote (see syntax below, for
the question): I like Mahbub Khandoker's code, but I was already writing this, another approach. It does not assume grants are applied for only in 2001-2005, which Mahbub's does; it does require that grant years are listed in non-decreasing order, as Mahbub's code does not. SPSS 15 draft output: List |-----------------------------|---------------------------| |Output Created |22-MAR-2007 13:53:04 | |-----------------------------|---------------------------| Dept# Grant1yr Grant2yr Grant3yr Grant4yr Grant5yr 1 2001 2001 2002 2002 . 2 2001 2002 2002 2002 . 3 2001 2001 2002 2002 2003 4 2002 2003 2004 2005 . 5 2004 2004 2005 2005 . 6 2001 2002 2003 2004 2005 7 2003 2004 2004 2004 . Number of cases read: 7 Number of cases listed: 7 * "I'd like to generate a variable that indicates the number of . * years that a department has applied for grants. For example, . * Dept. #1 has applied for 4 grants, but only applied in 2 years". NUMERIC YrsAppld (F3). VAR LABEL YrsAppld 'Number of years in which grant applied for'. VAL LABEL YrsAppld 99 'Yrs out of order'. MISSING VAL YrsAppld (99). NUMERIC #LtstYr (F4). COMPUTE YrsAppld = 0. COMPUTE #LtstYr = $SYSMIS. VECTOR GrantYr=Grant1yr TO Grant5yr. * The following logic relies on the years being in non-decreasing. * order in the vector. It does check, and return an error code . * if that's not the case. . LOOP #Grant = 1 TO 5. . DO IF NOT MISSING(GrantYr(#Grant)). . DO IF MISSING(#LtstYr) OR GrantYr(#Grant) GT #LtstYr. . COMPUTE #LtstYr = GrantYr(#Grant). . IF NOT MISSING (YrsAppld) YrsAppld = YrsAppld + 1. . ELSE IF GrantYr(#Grant) LT #LtstYr. . COMPUTE YrsAppld = 99. . END IF. . END IF. END LOOP. LIST. List |-----------------------------|---------------------------| |Output Created |22-MAR-2007 13:53:06 | |-----------------------------|---------------------------| Dept# Grant1yr Grant2yr Grant3yr Grant4yr Grant5yr YrsAppld 1 2001 2001 2002 2002 . 2 2 2001 2002 2002 2002 . 2 3 2001 2001 2002 2002 2003 3 4 2002 2003 2004 2005 . 4 5 2004 2004 2005 2005 . 2 6 2001 2002 2003 2004 2005 5 7 2003 2004 2004 2004 . 2 Number of cases read: 7 Number of cases listed: 7 =================== APPENDIX: Test data =================== * ............ Test data ............ . DATA LIST LIST SKIP=1 /Dept# Grant1yr Grant2yr Grant3yr Grant4yr Grant5yr. BEGIN DATA Dept. # 1st grant 2nd grant 3rd grant 4th grant 5th grant 1 2001 2001 2002 2002 2 2001 2002 2002 2002 3 2001 2001 2002 2002 2003 4 2002 2003 2004 2005 5 2004 2004 2005 2005 6 2001 2002 2003 2004 2005 7 2003 2004 2004 2004 END DATA. FORMATS Dept# (F3) /Grant1yr TO Grant5yr (F4). |
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In reply to this post by Mahbub Khandoker
Something seems to be going wrong with the find command in my version of
SPSS 14. There are times when I am searching for a certain word in a long sytnax file and I know it's there but the find command can't seem to find it. I can even copy a word like "freq" that's in the file a hundred times and past it into the find window and SPSS still tells me that it never appears in the file. This seems to only happen after I've searched for other commands first. Like I will search for "merge" and the find command will work find, but then it won't be able to find anything. I have to shut SPSS down and restart it to get the find function to work again. I've made sure I'm searching to correct file, that my cursor is at the top of the syntax file before I start searching, that I'm not highlighting any text etc and it still does it, even if I have my cursor on the exact word I'm searching for. I have to past the entire syntax file into text pad to find anything now. Does any one know why this is happening? -Graham |
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Graham -
I've experienced what you describe and I use SPSS v11.5. It can be very frustrating. My solution has been exactly what you seem to be doing, which is far from ideal. I am not sure what causes the problem or what the fix is, but I would be very interested. Peter -----Original Message----- From: SPSSX(r) Discussion [mailto:[hidden email]]On Behalf Of Graham Wright Sent: Thursday, March 22, 2007 11:21 AM To: [hidden email] Subject: find command Something seems to be going wrong with the find command in my version of SPSS 14. There are times when I am searching for a certain word in a long sytnax file and I know it's there but the find command can't seem to find it. I can even copy a word like "freq" that's in the file a hundred times and past it into the find window and SPSS still tells me that it never appears in the file. This seems to only happen after I've searched for other commands first. Like I will search for "merge" and the find command will work find, but then it won't be able to find anything. I have to shut SPSS down and restart it to get the find function to work again. I've made sure I'm searching to correct file, that my cursor is at the top of the syntax file before I start searching, that I'm not highlighting any text etc and it still does it, even if I have my cursor on the exact word I'm searching for. I have to past the entire syntax file into text pad to find anything now. Does any one know why this is happening? -Graham |
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In reply to this post by Graham Wright-2
Hi,
This seems to be a well known problem to SPSS. This is what I found on the SPSS website: ************************ " Problem Description: I'm using SPSS 14.0 for Windows and I'm having trouble with the Find/Replace function in the Syntax Editor. The one thing that I can consistently replicate is that a string that starts in the first character of the first line of a syntax file seems to be invisible to the Find dialog box. For instance, I have a syntax file that starts with a GET FILE command in that first position, first line -- and that's the only appearance of "get" in the file. If I try to Find (i.e., Edit->Find, or clicking the Binoculars in the toolbar) the string "get" the application responds with a "Not Found" message. If I then put either a single extra space or an extra line before the GET FILE command, then the Find function can find the "get" string. This problem is replicable -- it happens every single time, in 14.0.1 as well. What's wrong? Resolution Subject: This appears to be a defect Resolution Description: This is a defect and has been fixed in SPSS 15.0 for Windows. As a workaround if you have extended Find/Replaces to do as part of your editing, you could select all the text in your syntax file, and copy/paste to a simple text editor, such as NotePad or Programmer's File Editor. Perform your editing and then copy/paste your edited code back to the SPSS Syntax Editor and save. There have been other reported issues with the Find feature in SPSS 14.0 and 15.0 that we have not been able to consistently replicate, and thus cannot be certain have been fixed along with the other replicable issues. One example involves a file with over 50 instances of a particular string, but sporadically the Find/Replace dialog can only "see" the first instance -- clicking Find Next in the dialog box does not advance the cursor to the next instance. So far SPSS Development has not been able to replicate this issue in a controlled environment, but user reports indicate that closing and re-opening the syntax file does seem to "re-set" the Find dialog's functionality. SPSS 16.0 for Windows will use a new syntax editor and all Find/Replace functionality should work as expected in that release. We apologize for the inconvenience. " ******************************* Ana -----Original Message----- From: SPSSX(r) Discussion [mailto:[hidden email]] On Behalf Of peter link Sent: Thursday, March 22, 2007 2:43 PM To: [hidden email] Subject: Re: find command Graham - I've experienced what you describe and I use SPSS v11.5. It can be very frustrating. My solution has been exactly what you seem to be doing, which is far from ideal. I am not sure what causes the problem or what the fix is, but I would be very interested. Peter -----Original Message----- From: SPSSX(r) Discussion [mailto:[hidden email]]On Behalf Of Graham Wright Sent: Thursday, March 22, 2007 11:21 AM To: [hidden email] Subject: find command Something seems to be going wrong with the find command in my version of SPSS 14. There are times when I am searching for a certain word in a long sytnax file and I know it's there but the find command can't seem to find it. I can even copy a word like "freq" that's in the file a hundred times and past it into the find window and SPSS still tells me that it never appears in the file. This seems to only happen after I've searched for other commands first. Like I will search for "merge" and the find command will work find, but then it won't be able to find anything. I have to shut SPSS down and restart it to get the find function to work again. I've made sure I'm searching to correct file, that my cursor is at the top of the syntax file before I start searching, that I'm not highlighting any text etc and it still does it, even if I have my cursor on the exact word I'm searching for. I have to past the entire syntax file into text pad to find anything now. Does any one know why this is happening? -Graham |
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In reply to this post by Richard Ristow
Ok. Here's the Python way using SPSS 15 (you knew that was coming, right?). Others have posted pure SPSS ways of solving this problem that work, but the code below illustrates a general solution to counting distinct values in a group of variables without any extra assumptions.
Explanation after the code. begin program. import spss, spssaux, spssdata vardict = spssaux.VariableDict() curs = spssdata.Spssdata(accessType='w', indexes=vardict.range("Grant1yr", "Grant5yr")) curs.append(spssdata.vdef("YearsApplied", vlabel="Number of years with grant app", vfmt=("F",5,0))) curs.commitdict() for case in curs: yrs = set([]) for v in case: yrs.add(v) curs.casevalues([len(yrs)]) curs.CClose() end program. Explanation: vardict... creates a dictionary in Python of the SPSS variables. curs = ... gets a write cursor to the data and defines grant1yr TO grant5yr as the variables to retrieve making use of the range method of VariableDict objects. curs.append ... defines a new numeric variable and assigns a variable label and format. for case in curs ... loops over the data. yrs... makes use of the built-in set feature of Python, starting with an empty set for each case. for v ... adds each value of the SPSS variables retrieved to the set. It is the nature of sets that the elements are all distinct. So the curs.casevalues... line stores the size of the set, i.e., the number of distinct values in the new variable. -Jon Peck SPSS -----Original Message----- Dept. # 1st grant 2nd grant 3rd grant 4th grant 5th grant 1 2001 2001 2002 2002 2 2001 2002 2002 2002 3 2001 2001 2002 2002 2003 4 2002 2003 2004 2005 5 2004 2004 2005 2005 6 2001 2002 2003 2004 2005 7 2003 2004 2004 2004 I'd like to generate a variable that indicates the number of years that a department has applied for grants. For example, Dept. #1 has applied for 4 grants, but has only applied in 2 year, Dept. 4 has applied for 4 grants, but has applied in 4 years. |
Re: question about number of years applied
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Thanks everyone for all your help!
Miriam On 3/22/07, Peck, Jon <[hidden email]> wrote: > Ok. Here's the Python way using SPSS 15 (you knew that was coming, right?). Others have posted pure SPSS ways of solving this problem that work, but the code below illustrates a general solution to counting distinct values in a group of variables without any extra assumptions. > > Explanation after the code. > > begin program. > import spss, spssaux, spssdata > > vardict = spssaux.VariableDict() > curs = spssdata.Spssdata(accessType='w', indexes=vardict.range("Grant1yr", "Grant5yr")) > curs.append(spssdata.vdef("YearsApplied", vlabel="Number of years with grant app", vfmt=("F",5,0))) > curs.commitdict() > > for case in curs: > yrs = set([]) > for v in case: > yrs.add(v) > curs.casevalues([len(yrs)]) > curs.CClose() > end program. > > Explanation: > > vardict... creates a dictionary in Python of the SPSS variables. > curs = ... gets a write cursor to the data and defines grant1yr TO grant5yr as the variables to retrieve making use of the range method of VariableDict objects. > curs.append ... defines a new numeric variable and assigns a variable label and format. > > for case in curs ... loops over the data. > yrs... makes use of the built-in set feature of Python, starting with an empty set for each case. > for v ... adds each value of the SPSS variables retrieved to the set. It is the nature of sets that the elements are all distinct. > So the curs.casevalues... line stores the size of the set, i.e., the number of distinct values in the new variable. > > -Jon Peck > SPSS > > > -----Original Message----- > Dept. # 1st grant 2nd grant 3rd grant 4th grant 5th grant > 1 2001 2001 2002 2002 > 2 2001 2002 2002 2002 > 3 2001 2001 2002 2002 > 2003 > 4 2002 2003 2004 2005 > 5 2004 2004 2005 2005 > 6 2001 2002 2003 2004 > 2005 > 7 2003 2004 2004 2004 > > I'd like to generate a variable that indicates the number of years that a department has applied for grants. For example, Dept. #1 has applied for 4 grants, but has only applied in 2 year, Dept. 4 has applied for 4 grants, but has applied in 4 years. > |
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In reply to this post by Ana Luebbers
Man, anyone else find that frustrating?!
I have a problem being told to buy an upgrade in order to fix a 'bug' on a feature which SHOULD have been working to begin with. I think we should at least get a patch for it. I certainly don't mind upgrading in order to get a new FEATURE, but not an existing one fixed. Debbie Butler SCP Modeling Analyst Frito Lay Operations 972.334.3934 -----Original Message----- From: SPSSX(r) Discussion [mailto:[hidden email]] On Behalf Of Ana Luebbers Sent: Thursday, March 22, 2007 1:58 PM To: [hidden email] Subject: Re: find command Hi, This seems to be a well known problem to SPSS. This is what I found on the SPSS website: ************************ " Problem Description: I'm using SPSS 14.0 for Windows and I'm having trouble with the Find/Replace function in the Syntax Editor. The one thing that I can consistently replicate is that a string that starts in the first character of the first line of a syntax file seems to be invisible to the Find dialog box. For instance, I have a syntax file that starts with a GET FILE command in that first position, first line -- and that's the only appearance of "get" in the file. If I try to Find (i.e., Edit->Find, or clicking the Binoculars in the toolbar) the string "get" the application responds with a "Not Found" message. If I then put either a single extra space or an extra line before the GET FILE command, then the Find function can find the "get" string. This problem is replicable -- it happens every single time, in 14.0.1 as well. What's wrong? Resolution Subject: This appears to be a defect Resolution Description: This is a defect and has been fixed in SPSS 15.0 for Windows. As a workaround if you have extended Find/Replaces to do as part of your editing, you could select all the text in your syntax file, and copy/paste to a simple text editor, such as NotePad or Programmer's File Editor. Perform your editing and then copy/paste your edited code back to the SPSS Syntax Editor and save. There have been other reported issues with the Find feature in SPSS 14.0 and 15.0 that we have not been able to consistently replicate, and thus cannot be certain have been fixed along with the other replicable issues. One example involves a file with over 50 instances of a particular string, but sporadically the Find/Replace dialog can only "see" the first instance -- clicking Find Next in the dialog box does not advance the cursor to the next instance. So far SPSS Development has not been able to replicate this issue in a controlled environment, but user reports indicate that closing and re-opening the syntax file does seem to "re-set" the Find dialog's functionality. SPSS 16.0 for Windows will use a new syntax editor and all Find/Replace functionality should work as expected in that release. We apologize for the inconvenience. " ******************************* Ana -----Original Message----- From: SPSSX(r) Discussion [mailto:[hidden email]] On Behalf Of peter link Sent: Thursday, March 22, 2007 2:43 PM To: [hidden email] Subject: Re: find command Graham - I've experienced what you describe and I use SPSS v11.5. It can be very frustrating. My solution has been exactly what you seem to be doing, which is far from ideal. I am not sure what causes the problem or what the fix is, but I would be very interested. Peter -----Original Message----- From: SPSSX(r) Discussion [mailto:[hidden email]]On Behalf Of Graham Wright Sent: Thursday, March 22, 2007 11:21 AM To: [hidden email] Subject: find command Something seems to be going wrong with the find command in my version of SPSS 14. There are times when I am searching for a certain word in a long sytnax file and I know it's there but the find command can't seem to find it. I can even copy a word like "freq" that's in the file a hundred times and past it into the find window and SPSS still tells me that it never appears in the file. This seems to only happen after I've searched for other commands first. Like I will search for "merge" and the find command will work find, but then it won't be able to find anything. I have to shut SPSS down and restart it to get the find function to work again. I've made sure I'm searching to correct file, that my cursor is at the top of the syntax file before I start searching, that I'm not highlighting any text etc and it still does it, even if I have my cursor on the exact word I'm searching for. I have to past the entire syntax file into text pad to find anything now. Does any one know why this is happening? -Graham |
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In reply to this post by Miriam L. Gerver
A colleague reminded me that the solution below is more complicated than needed. This revised code takes advantage of the ability to form a set from a sequence of values. The variable case is a sequence of values of the selected variables, so the code can simply pass this to set and take the size of the set in one step.
And while we're on the topic of sets, I want to point out that Python has all the set operators you learned about in school: union, intersections, difference, symmetric difference ... -Jon Peck begin program. import spss, spssaux, spssdata vardict = spssaux.VariableDict() curs = spssdata.Spssdata(accessType='w', indexes=vardict.range("grant1yr", "grant5yr")) curs.append(spssdata.vdef("YearsApplied", vlabel="Number of years with grant app", vfmt=("F",5,0))) curs.commitdict() for case in curs: curs.casevalues([len(set(case))]) curs.CClose() end program. -----Original Message----- From: Peck, Jon Sent: Thursday, March 22, 2007 2:48 PM To: 'Richard Ristow'; [hidden email] Subject: RE: Re: [SPSSX-L] question about number of years applied Ok. Here's the Python way using SPSS 15 (you knew that was coming, right?). Others have posted pure SPSS ways of solving this problem that work, but the code below illustrates a general solution to counting distinct values in a group of variables without any extra assumptions. Explanation after the code. begin program. import spss, spssaux, spssdata vardict = spssaux.VariableDict() curs = spssdata.Spssdata(accessType='w', indexes=vardict.range("Grant1yr", "Grant5yr")) curs.append(spssdata.vdef("YearsApplied", vlabel="Number of years with grant app", vfmt=("F",5,0))) curs.commitdict() for case in curs: yrs = set([]) for v in case: yrs.add(v) curs.casevalues([len(yrs)]) curs.CClose() end program. Explanation: vardict... creates a dictionary in Python of the SPSS variables. curs = ... gets a write cursor to the data and defines grant1yr TO grant5yr as the variables to retrieve making use of the range method of VariableDict objects. curs.append ... defines a new numeric variable and assigns a variable label and format. for case in curs ... loops over the data. yrs... makes use of the built-in set feature of Python, starting with an empty set for each case. for v ... adds each value of the SPSS variables retrieved to the set. It is the nature of sets that the elements are all distinct. So the curs.casevalues... line stores the size of the set, i.e., the number of distinct values in the new variable. -Jon Peck SPSS -----Original Message----- Dept. # 1st grant 2nd grant 3rd grant 4th grant 5th grant 1 2001 2001 2002 2002 2 2001 2002 2002 2002 3 2001 2001 2002 2002 2003 4 2002 2003 2004 2005 5 2004 2004 2005 2005 6 2001 2002 2003 2004 2005 7 2003 2004 2004 2004 I'd like to generate a variable that indicates the number of years that a department has applied for grants. For example, Dept. #1 has applied for 4 grants, but has only applied in 2 year, Dept. 4 has applied for 4 grants, but has applied in 4 years. |
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In reply to this post by Butler, Deborah {FLNA}
Yeah, and I use SPSS through an academic site license, so upgrading is
not option. This seems to be yet another thing that Stata and SAS can do just fine on their own but I have to pay extra to get SPSS to do (like give correct ci's for complex weighting schemes).... -Graham Butler, Deborah {FLNA} wrote: > Man, anyone else find that frustrating?! > > I have a problem being told to buy an upgrade in order to fix a 'bug' on > a feature which SHOULD have been working to begin with. I think we > should at least get a patch for it. I certainly don't mind upgrading in > order to get a new FEATURE, but not an existing one fixed. > > > Debbie Butler > SCP Modeling Analyst > Frito Lay Operations > 972.334.3934 > > -----Original Message----- > From: SPSSX(r) Discussion [mailto:[hidden email]] On Behalf Of > Ana Luebbers > Sent: Thursday, March 22, 2007 1:58 PM > To: [hidden email] > Subject: Re: find command > > Hi, > > This seems to be a well known problem to SPSS. This is what I found on > the SPSS website: > > ************************ > " Problem Description: I'm using SPSS 14.0 for Windows and I'm having > trouble with the Find/Replace function in the Syntax Editor. The one > thing that I can consistently replicate is that a string that starts in > the first character of the first line of a syntax file seems to be > invisible to the Find dialog box. > > For instance, I have a syntax file that starts with a GET FILE command > in that first position, first line -- and that's the only appearance of > "get" in the file. If I try to Find (i.e., Edit->Find, or clicking the > Binoculars in the toolbar) the string "get" the application responds > with a "Not Found" message. If I then put either a single extra space or > an extra line before the GET FILE command, then the Find function can > find the "get" string. This problem is replicable -- it happens every > single time, in 14.0.1 as well. > > What's wrong? > > Resolution Subject: This appears to be a defect > > Resolution Description: > This is a defect and has been fixed in SPSS 15.0 for Windows. As a > workaround if you have extended Find/Replaces to do as part of your > editing, you could select all the text in your syntax file, and > copy/paste to a simple text editor, such as NotePad or Programmer's File > Editor. Perform your editing and then copy/paste your edited code back > to the SPSS Syntax Editor and save. > > There have been other reported issues with the Find feature in SPSS 14.0 > and 15.0 that we have not been able to consistently replicate, and thus > cannot be certain have been fixed along with the other replicable > issues. One example involves a file with over 50 instances of a > particular string, but sporadically the Find/Replace dialog can only > "see" the first instance -- clicking Find Next in the dialog box does > not advance the cursor to the next instance. So far SPSS Development has > not been able to replicate this issue in a controlled environment, but > user reports indicate that closing and re-opening the syntax file does > seem to "re-set" the Find dialog's functionality. SPSS 16.0 for Windows > will use a new syntax editor and all Find/Replace functionality should > work as expected in that release. > > We apologize for the inconvenience. " > > ******************************* > > > Ana > > -----Original Message----- > From: SPSSX(r) Discussion [mailto:[hidden email]] On Behalf Of > peter link > Sent: Thursday, March 22, 2007 2:43 PM > To: [hidden email] > Subject: Re: find command > > Graham - > > I've experienced what you describe and I use SPSS v11.5. It can be very > frustrating. My solution has been exactly what you seem to be doing, > which > is far from ideal. I am not sure what causes the problem or what the > fix > is, but I would be very interested. > > Peter > > -----Original Message----- > From: SPSSX(r) Discussion [mailto:[hidden email]]On Behalf Of > Graham Wright > Sent: Thursday, March 22, 2007 11:21 AM > To: [hidden email] > Subject: find command > > > Something seems to be going wrong with the find command in my version of > SPSS 14. There are times when I am searching for a certain word in a > long sytnax file and I know it's there but the find command can't seem > to find it. I can even copy a word like "freq" that's in the file a > hundred times and past it into the find window and SPSS still tells me > that it never appears in the file. This seems to only happen after I've > searched for other commands first. Like I will search for "merge" and > the find command will work find, but then it won't be able to find > anything. I have to shut SPSS down and restart it to get the find > function to work again. I've made sure I'm searching to correct file, > that my cursor is at the top of the syntax file before I start > searching, that I'm not highlighting any text etc and it still does it, > even if I have my cursor on the exact word I'm searching for. I have to > past the entire syntax file into text pad to find anything now. Does any > one know why this is happening? > > -Graham > |
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