The “correct proportion” for the null hypothesis depends on how you define the null task. This would be clearer if you had a control condition of some sort. E.g. where the original lists were unrelated to the stimulus words or were presented aurally as opposed to visually etc.
As you don’t have a control group, you are simply measuring a false alarm rate. It is 55% which means that there is a strong tendency for false memory to occur in the task you studied. You could test whether that rate differs significantly from rates obtained by other researchers in other tasks.
Garry Gelade
Business Analytic
From: SPSSX(r) Discussion [mailto:[hidden email]] On Behalf Of Rose, Fred
Sent: 18 April 2012 22:32
To: [hidden email]
Subject: Re: Frequency analysis
That is a definite issue – I’m not sure of the correct chance proportions would be. For those not familiar with the task, participants read a list of words such as “moth insect wing bird fly bug cocoon color net” and ask recall or recognition. The false memory occurs when a participant falsely remembers the critical word – in this case, “butterfly”. I don’t think it’s correct to say that 50% is the correct chance proportion but I’m not sure what a correct value would be. It is likely that a 55% false memory rate is higher than false alarm rate on a word list task where the list consists of unrelated words, but again, I’m not sure where to go with it. The bottom line is that I would like to be able to claim that the 55% rate reflects a strong tendency for false memory to occur.
On 4/18/12 1:49 PM, "Bruce Weaver" <bruce.weaver@...> wrote:
It sounds like you're looking for the binomial test. It's not clear what
proportions you expect in the two categories by chance, but if it was 50%,
the command would look like this (where "recalled" is an indicator variable
for recall, 0=No, 1=Yes):
NPAR TESTS
/BINOMIAL (0.50)=recalled
/MISSING ANALYSIS.
HTH.
Rose, Fred wrote
--
Fredric E. Rose, Ph.D.
Associate Professor of Psychology
Palomar College
760-744-1150 x2344
frose@...
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