Dear List: I just used Hayes’ Process macro within spss 23.0 to test for an indirect mediational effect and have a result which is a little confusing. The print out for
the indirect effect shows that the 95% CI for the indirect coefficient is -0.00097 (lower Limit) and 0.25978 (Upper limit) with a Z value of 2.09 and a p value of .03641. Since the 95% CI includes zero the results are not statistically significant yet the
p value is statistically significant. Is this inconsistency due the p value representing only one tail whereas the 95% CI utilizes two tails (which would relate to .03641 X 2 = .07282 and thus would include zero contained within the 95% CI)? I looked at another
result where the Z value was 0.95 and it had a p value of .34338 which, to me, suggests that this value represents .17169 in each tail or a total p value of .34338. If this is correct then the p value for the Z of 2.09 actually is .018205 in one tail and .03641
in two tails (.018205 X 2 = .03641). If so then the 95% CI should not contain the value of zero. What am I missing?
Martin F. Sherman, Ph.D.
Professor of Psychology
Director of Master’s Education: Thesis Track
Department of Psychology
222 B Beatty Hall
4501 North Charles Street
Baltimore, MD 21210
410-617-2417 tel
410-617-5341 fax
Free forum by Nabble | Edit this page |