If the definition of exponentiation of real numbers is extended to allow negative results then the result is no longer well-behaved.
Neither the logarithm method nor the rational exponent method can be used to define br as a real number for a negative real number b and an arbitrary real number r. Indeed, er is positive for every real number r, so ln(b) is not defined as a real number for b ≤ 0.
The rational exponent method cannot be used for negative values of b because it relies on continuity. The function f(r) = br has a unique continuous extension[15] from the rational numbers to the real numbers for each b > 0. But when b < 0, the function f is not even continuous on the set of rational numbers r for which it is defined.
For example, consider b = −1. The nth root of −1 is −1 for every odd natural number n. So if n is an odd positive integer, (−1)(m/n) = −1 if m is odd, and (−1)(m/n) = 1 if m is even. Thus the set of rational numbers q for which (−1)q = 1 is dense in the rational numbers, as is the set of q for which (−1)q = −1. This means that the function (−1)q is not continuous at any rational number q where it is defined.
On the other hand, arbitrary complex powers of negative numbers b can be defined by choosing a complex logarithm of b.
I don't know if there is any demand, but I think the square root of -1
is used in electronics. I'm not into this so I really don't know. I did
not pose this question because I have an application for it. I was just
curious since it seems that sophisticated software packages like SPSS
and SAS should be able to do it. I just sent an email to join the SAS
discussion group and will ask them if SAS can do it. I suppose one could
write a routine to return a -1 if the the denominator of the exponent is
an odd number.
Stan
On 11/15/2019 10:05 AM, Rich Ulrich wrote:
> I wonder - Is there any demand for the exception-coding
> that would be necessary? How many people write code
> where they want to take the fractional root of a negative
> number, where the fraction is the reciprocal of an odd integer?
> ( Note, the fraction cannot be expressed EXACTLY on a binary
> computer. How is that accommodated?)
>
> The natural programming solution to non-integer roots is
> to use logs. I suppose if there is an area where the problem
> comes up, specialized programs for that area might do it.
> I suspect the efficient solution might use a special subroutine
> call rather than an in-line expression.
>
> --
> Rich Ulrich
>
> ------------------------------------------------------------------------
> *From:* SPSSX(r) Discussion <[hidden email]> on behalf of
> Bruce Weaver <[hidden email]>
> *Sent:* Friday, November 15, 2019 11:35 AM
> *To:* [hidden email] <[hidden email]>
> *Subject:* Re: Roots
> https://www.ibm.com/support/knowledgecenter/en/SSLVMB_26.0.0/statistics_reference_project_ddita/spss/base/syn_transformation_expressions_domain_errors.html
>
>
>
> Kirill Orlov wrote
> > See DOMAIN ERRORS paragraph in Command Syntax Reference.
> >
> >
> > 15.11.2019 4:53, Stan Gorodenski пишет:
> >> compute z = (-1)**(1/3).
> >
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