Simple Macro Question
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I'm making some generic syntax using a macro and have ran into a snag. When I use the syntax below I end up getting the error: ">Error # 1. Command name: /METHOD >The first word in the line is not recognized as an SPSS command. >This command not executed."
Any ideas how to solve this error?
*********************************************** Define Scales ***********************************************
DEFINE !Scale1 ( ) scale !ENDDEFINE. DEFINE !Outcome1 () Outcome !ENDDEFINE.
*********************************************** Outcome Results ***********************************************
UNIANOVA !Outcome1 BY !Scale1 /METHOD = SSTYPE(3) /INTERCEPT = INCLUDE /PRINT = DESCRIPTIVE /CRITERIA = ALPHA(.05) /DESIGN = !Scale1 . |
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The program has decided that a new command
begins with /METHOD. It looks in your post like the line before that is empty,
which would cause that, but cutting and pasting in e-mail often adds empty
lines that weren’t there in the original, so we can’t be sure. Jonathan Fry From: SPSSX(r)
Discussion [mailto:[hidden email]] On
Behalf Of Craig Johnson I'm making some
generic syntax using a macro and have ran into a snag. When I use the
syntax below I end up getting the error: ">Error # 1. Command name: /METHOD >The first word in
the line is not recognized as an SPSS command. >This command not
executed." Any ideas how to solve this error? *********************************************** Define Scales *********************************************** DEFINE !Scale1 ( ) scale !ENDDEFINE. DEFINE !Outcome1 () Outcome !ENDDEFINE. *********************************************** Outcome Results *********************************************** UNIANOVA !Outcome1 BY !Scale1 /METHOD = SSTYPE(3) /INTERCEPT = INCLUDE /PRINT = DESCRIPTIVE /CRITERIA = ALPHA(.05) /DESIGN = !Scale1 . |
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Macros insert a return after the macro is executed: (reformatted to eliminate spaces before/ after paragraphs): This should work UNIANOVA !Outcome1 BY !Scale1 / METHOD = SSTYPE(3) /INTERCEPT = INCLUDE /PRINT = DESCRIPTIVE /CRITERIA = ALPHA(.05) /DESIGN = !Scale1 . Try running the macro with SET MPRINT = on. Before the macro Jim Marks Director, Market Research x1616 From: SPSSX(r) Discussion
[mailto:[hidden email]] On Behalf Of Fry, Jonathan B. The program has decided that a new command begins with
/METHOD. It looks in your post like the line before that is empty, which
would cause that, but cutting and pasting in e-mail often adds empty lines that
weren’t there in the original, so we can’t be sure. Jonathan Fry From: SPSSX(r) Discussion
[mailto:[hidden email]] On Behalf Of Craig Johnson I'm
making some generic syntax using a macro and have ran into a snag. When I
use the syntax below I end up getting the error: ">Error # 1. Command
name: /METHOD >The first word in the line is not recognized as an SPSS
command. >This command not executed." Any ideas how to
solve this error? *********************************************** Define Scales *********************************************** DEFINE !Scale1 (
) scale !ENDDEFINE. DEFINE !Outcome1
() Outcome !ENDDEFINE. *********************************************** Outcome Results *********************************************** UNIANOVA
!Outcome1 BY !Scale1
/METHOD = SSTYPE(3)
/INTERCEPT = INCLUDE
/PRINT = DESCRIPTIVE
/CRITERIA = ALPHA(.05)
/DESIGN = !Scale1 . |
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In reply to this post by Fry, Jonathan B.
In older versions, there are issues with
ending a line with a macro call, which results in the generated code including
a blank line in the middle of the command, which is interpreted as a command
terminator. Try putting the /METHOD subcommand on the same line !Outcome1 BY !Scale1. From: SPSSX(r)
Discussion [mailto:[hidden email]] On
Behalf Of Fry, Jonathan B. The program has decided that a new command
begins with /METHOD. It looks in your post like the line before that is
empty, which would cause that, but cutting and pasting in e-mail often adds
empty lines that weren’t there in the original, so we can’t be
sure. Jonathan Fry From: SPSSX(r)
Discussion [mailto:[hidden email]] On
Behalf Of Craig Johnson I'm making some
generic syntax using a macro and have ran into a snag. When I use the
syntax below I end up getting the error: ">Error # 1. Command name: /METHOD >The first word in
the line is not recognized as an SPSS command. >This command not
executed." Any ideas how to solve this error? *********************************************** Define Scales *********************************************** DEFINE !Scale1 ( ) scale !ENDDEFINE. DEFINE !Outcome1 () Outcome !ENDDEFINE. *********************************************** Outcome Results *********************************************** UNIANOVA !Outcome1 BY !Scale1 /METHOD = SSTYPE(3) /INTERCEPT = INCLUDE /PRINT = DESCRIPTIVE /CRITERIA = ALPHA(.05) /DESIGN = !Scale1 . |
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In reply to this post by Craig Johnson
It
looks like your "scale" parameter contains a period which SPSS inteprets as
end of command, is that the case? Which value(s) does scale
take?
Luca
Da: SPSSX(r) Discussion [mailto:[hidden email]] Per conto di Craig Johnson Inviato: lunedì 9 febbraio 2009 19.57 A: [hidden email] Oggetto: Simple Macro Question I'm making some generic syntax using a macro and have ran into a snag. When I use the syntax below I end up getting the error: ">Error # 1. Command name: /METHOD >The first word in the line is not recognized as an SPSS command. >This command not executed."
Any ideas how to solve this error?
*********************************************** Define Scales ***********************************************
DEFINE !Scale1 ( ) scale !ENDDEFINE. DEFINE !Outcome1 () Outcome !ENDDEFINE.
*********************************************** Outcome Results ***********************************************
UNIANOVA !Outcome1 BY !Scale1 /METHOD = SSTYPE(3) /INTERCEPT = INCLUDE /PRINT = DESCRIPTIVE /CRITERIA = ALPHA(.05) /DESIGN = !Scale1 . |
Can the denominator for a bar chart representing percentage be specified?
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Dearest listers, I would like to create a series of bar
charts. The chart consists of several categorical variables, community health clinics.
I want to be able to see the percent of individuals with and without chronic
diseases that are assigned to a clinic as their pcp who have visited that
clinic. The numbers of individuals assigned to the clinic does not enter into
the graph, it merely represents the number of individuals that have visited the
clinic, either with or without chronic illnesses. From that information the
only percentage that I can get by default for a clinic is the percentage of
individuals that have chronic vs nonchronic conditions who have visited the
clinic. I want to specify the already known numbers. How can I create graphs
that use the total number of individuals with chronic diseases assigned to that
clinic as their pcp as the denominator in the percentage calculation, or is
that not possible? The denominators would therefore be different for each
clinic, and different within each clinic based on chronic vs nonchronic conditions. Please let me know if you can help, or if
this is unclear. Thanks Matt Matthew Pirritano, Ph.D. Research Analyst IV Medical Services Initiative (MSI) Orange County Health Care Agency (714) 568-5648 |
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